1/6 - 0,4 . 5/8 + 1/2
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Đề vẫn giải được nhưng số khá xấu, không phù hợp với lớp 7. Bạn xem lại xem đã đúng đề chưa vậy>
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\(\dfrac{-19}{2}\) < a < \(\dfrac{-20}{3}\)
- \(\dfrac{57}{6}\) < a < \(\dfrac{-40}{6}\)
a = - 56/6; -55/6; -54/6; - 53/6; - 52/6; - 51/6; ......; -42/6; -41/6
b, \(\dfrac{1}{3}\) < \(\dfrac{4}{b}\) < \(\dfrac{1}{2}\)
\(\dfrac{4}{12}\) < \(\dfrac{4}{b}\)< \(\dfrac{4}{8}\)
b = 11; 10; 9
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2(x-3)+3(x+1)=4x-1
=>2x-6+3x+3=4x-1
=> 2x+3x-4x=-1+6-3
=> x(2+3-4)=2
=>x=2
Vậy x=2
\(2\times\left(x-3\right)+3\times\left(x+1\right)=4x-1\)
\(2x-6+3x+3=4x-1\)
\(\Rightarrow2x-6+3x+3-\left(4x-1\right)=0\)
\(2x-6+3x+3-4x+1=0\)
\(2x+3x-4x-6+3+1=0\)
\(\left(2+3-4\right)x-\left(6-3-1\right)=0\)
\(x-2=0\)
\(x=0+2\)
\(x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
2(x-3)+3(x+1)=4x-1
=>2x-6+3x+3=4x-1
=> 2x+3x-4x=-1+6-3
=> x(2+3-4)=2
=>x=2
Vậy x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
- \(\dfrac{5}{6}\) + 3\(x\) = \(\dfrac{2}{3}\) - \(\dfrac{1}{2}\)\(x\)
3\(x\) + \(\dfrac{1}{2}\)\(x\) = \(\dfrac{2}{3}\) + \(\dfrac{5}{6}\)
\(\dfrac{7x}{2}\) = \(\dfrac{3}{2}\)
\(x\) = \(\dfrac{3}{2}\) : \(\dfrac{7}{2}\)
\(x\) = \(\dfrac{3}{7}\)
\(\dfrac{1}{6}\) - 0,4 . \(\dfrac{5}{8}\) + \(\dfrac{1}{2}\)
= \(\dfrac{1}{6}\) - \(\dfrac{1}{4}\) + \(\dfrac{1}{2}\)
= \(\dfrac{2}{12}\) - \(\dfrac{3}{12}\) + \(\dfrac{6}{12}\)
= \(\dfrac{5}{12}\)
1/6-0,4.5/8+1/2
=1/6-1/4+1/2
=2/12-3/12+6/12
=5/12