A=D

B=G

C=E

Our family lives in a big apartment in the city centre. There are four ....rooms........, a living room, a kitchen and two bathrooms. The living room is next to the kitchen. There is a bookshelf....between..........them. In the living room, we hang many....pictures.......on the wall. There is also a sofa and a coffee table.

The most favourite place in my bedroom. I have many ....posters.......on the wall about my favourite music bands. There is also a ...piano....... I can play my favourite songs when I am stressed.

Our family lives in a big apartment in the city centre. There are four ...bedrooms.., a living room, a kitchen and two bathrooms. The living room is next to the kitchen. There is a bookshelf......between.....them. In the living room, we hang many....pictures...on the wall. There is also a sofa and a coffee table.

The most favourite place in my bedroom. I have many ..posters...on the wall about my favourite music bands. There is also a ..piano. I can play my favourite songs when I am stressed.

1) The kitchen has many chairs 

2) Nam doesn't live in countryside

3) I live with my parents and my brother

4) The picture is behind the television

5) I only watch TV in the living room

sorry pé ms lp 6 năm nay lp 7

Nếu p = 2 

=> p + 4 = 6 (loại) 

Nếu p = 3

=> p + 4 = 7 (tm)

=> p + 14 = 17 (tm)

Nếu p > 3

=> \(\orbr{\begin{cases}p=3k+1\\p=3k+2\end{cases}}\)

Khi p = 3k + 1 

=> p + 14 = 3k + 1 + 14 = 3k + 15 = 3(k + 5) \(⋮\)3 

=> p + 14 là hợp số (loại)

Khi p = 3k + 2

=> p + 4 = 3k + 2 + 4 = 3k + 6 = 3(k + 2) \(⋮\)3 (loại)

=> p + 4 là hợp số (loại)

Vậy p = 3

\(fx-f(x-1)=x \)

\(f=x\)

\(f-x=0\)

\(-(x-f)=0\)

\(x-f=0\)

học tốt

ta có 

\(S=\frac{1}{10}+\frac{1}{20}+\frac{1}{35}+\frac{1}{56}+\frac{1}{84}+\frac{1}{120}+\frac{1}{165}+\frac{1}{220}\)

\(=6\left(\frac{1}{3\cdot4\cdot5}+\frac{1}{4\cdot5\cdot6}+\frac{1}{6\cdot7\cdot8}+\frac{1}{8\cdot9\cdot10}+\frac{1}{10\cdot11\cdot12}\right)\)

\(=3\left(\frac{1}{3\cdot4}-\frac{1}{11\cdot12}\right)=\frac{5}{22}\)

a) \(5x^2-2x\left(3x+\frac{3}{2}\right)=-x^2-3x=-x\left(x+3\right)=-3\left(3+3\right)=-18\)

b) \(3x\left(x-4y\right)-\frac{12}{5}y\left(y-5x\right)=3x^2-\frac{12}{5}y^2=3\left(x^2-\frac{4}{5}y^2\right)\)

\(=3\left(4^2-\frac{4}{5}.5^2\right)=3.\left(-4\right)=-12\)

c) \(\left(x-2\right)^2-\left(x+7\right)\left(x-7\right)=x^2-4x+4-x^2+49=-4x+53=-4.3+53=41\)

d) \(x^2+12x+36=\left(x+6\right)^2=\left(64+6\right)^2=70^2=4900\)

e) \(\left(x-3\right)^2-\left(x-4\right)\left(x+4\right)=x^2-6x+9-x^2+16=-6x+25=-6\left(-1\right)+25\)

= 31

f) \(\left(3x+2y\right)^2-4y\left(3x+y\right)=9x^2+12xy+4y^2-12xy-4y^2=9x^2=9\left(-\frac{1}{3}\right)^2=1\)

a, \(5x^2-2x\left(3x+\frac{3}{2}\right)=-x^2-3x\)

Thay x = 3 vào biểu thức trên ta cs : \(-3^2-3.3=-9-9=-18\)

b, \(3x\left(x-4y\right)-\frac{12}{5}y\left(y-5x\right)=3x^2-\frac{12}{5}y^2\)

Thay x = 4 ; y = 5 vào biểu thức trên ta có : \(3.4^2-\frac{12}{5}.5^2=-12\)