giúp mình với

1) 51 = 3.17

2) 80 = 2⁴.5

3) 75 = 3.5²

4) 180 = 2².3².5

5, 105 = 3.5.7

6, 540  = 2².3³.5

7, 256 = 2⁸

8, 840 = 2³.3.5.7

Có tất cả các số trên dãy là:  (202-2):4+1=51(số)

Tổng dãy số trên là: (202+2)x51:2=5202

\(9^{12}.19-3^{24}.19\\ =\left(3^2\right)^{12}.19-3^{24}.19\\ =3^{24}.19-3^{24}.19=0\)

ét o ét

2^x+1 -2^x-1 = 5² - 5⁰

2^x+1 - 2^x-1 = 24

2^x-1.(2²-1) = 24

2^x-1.3 = 24

2^x-1 = 24 : 3

2^x-1 = 8

2^x-1 = 2³

x - 1 = 3

x = 4

2^x = 5²

2x+1 -2x-1 = 52 - 50

2x+1 - 2x-1 = 24

2x-1.(22-1) = 24

2x-1.3 = 24

2x-1 = 24 : 3

2x-1 = 8

2x-1 = 23

x - 1 = 3

x = 4

2x = 52

`3^(x+1) +3^x =36`

`3^x( 3^1 +1) =36`

`3^x * (3+1) =36`

`4*3^x =36`

`3^x =36/4 =9`

`3^=3^2`

`=> x=2`

Ta có: 

\(A=2020^{2023}-2020^{2022}=2020^{2022}\left(2020-1\right)=2019.2020^{2022}\\ B=2020^{2022}-2020^{2021}=2020^{2021}\left(2020-1\right)=2019.2020^{2021}\)

\(A-B=2019.2020^{2022}-2019.2020^{2021}=2019.2020^{2021}\left(2020-1\right)>0\\ \Rightarrow A>B\)

$A=2020^{2023}-2020^{2022}=2020^{2022}\left(2020-1\right)=2019.2020^{2022}B=2020^{2022}-2020^{2021}=2020^{2021}\left(2020-1\right)=2019.2020^{2021}$

$A-B=2019.2020^{2022}-2019.2020^{2021}=2019.2020^{2021}\left(2020-1\right)>0\Rightarrow A>B$

`(x-4)^3 :2^5 = 16`

`(x-4)^3 = 16 *2^5 = 16* 32`

`(x-4)^3 = 512`

`(x-4)^3 = 8^3`

`x-4 =8`

`x= 8+4=12`

\(\left\{132-\left[116-\left(16-8\right)\right]:2\right\}.5\)

\(=\left\{132-\left[116-8\right]:2\right\}.5\)

\(=\left\{132-108:2\right\}.5\)

\(=390\)

{ 132 -  [116 - ( 16 - 8 )] : 2 } . 5

={ 132 -  [116 - ( 8 )] : 2 } . 5

={ 132 -  [108 )] : 2 } . 5

={ 132 -  54 } . 5

=78 .5

=390

(10\100)

giúp em đi ạ

\(5^6:5^4+3.3^2-80\)

\(=5^2+27-80\)

\(=25+27-80=-28\)

x=3

\(3.5^x-8=367\)

\(\Leftrightarrow3.5^x=375\)

\(\Leftrightarrow5^x=125\)

\(\Leftrightarrow x=3\)