A = 1/2000.2001+1/2001.2002+1/2002.2003 = 2000.20109915 nhé :3

\(\left(1\frac{1}{2}-0,5\right):\left(-3\right)^2+\frac{1}{3}-\frac{1}{6}\)

\(=\left(\frac{3}{2}-\frac{1}{2}\right):9+\frac{1}{6}\)

\(=1:9+\frac{1}{6}\)\(=\frac{1}{9}+\frac{1}{6}=\frac{5}{18}\)

\(\left(1\frac{1}{2}-0,5\right)\div\left(-3\right)^2+\frac{1}{3}-\frac{1}{6}\)

\(=\left(\frac{3}{2}-\frac{1}{2}\right)\div9+\frac{1}{6}\)

\(=1\div9+\frac{1}{6}\)

\(=\frac{1}{9}+\frac{1}{6}\)

\(=\frac{5}{18}\)

\(2\frac{1}{2}:\left(\frac{5}{2}-3\frac{3}{4}\right)+\left(\frac{-1}{2}\right)^2\)

\(=\frac{5}{2}:\left(\frac{10}{4}-\frac{15}{4}\right)+\frac{1}{4}\)

\(=\frac{5}{2}:\frac{-5}{4}+\frac{1}{4}\)

\(=-2+\frac{1}{4}=\frac{-7}{4}\)

nhanh v

bằng 1,732050808

5^x+1 - 5^x = 100 . 25²⁹

5^x . 5 - 5^x = 100  .  25²⁹

5^x . ( 5 - 1 ) = 100 . 25²⁹

5^x.: 4 = 100 . 25²⁹

5^x : 25²⁹ = 100 : 4

5^x : 25²⁹  = 25

5^x = 25 . 25²⁹

5^x = 25³⁰

5^x = (5²)³⁰

5^x = 5⁶⁰ 

=> x = 60

\(a,x.x=-5.-5\)

\(x^2=25< =>5^2=25=>x=5\)Vậy x=5

\(b,-2.8=x.-x\)

\(-16=-\left(x^2\right)< =>-16=-\left(4^2\right)=>x=4\)Vậy x=4

\(c,\left(x+1\right)\left(x+1\right)=4.9\)

\(\left(x+1\right)^2=36\)

\(\left(x+1\right)^2=6^2\)

\(< =>x+1=6\)

\(x=5\)

Vậy x=5

bằng em không biết hihi

(-2,5)^2= ?

Trả lời:

(-2,5)²=(-2,5).(-2,5)=6,25

Giải :

( - 2,5 )² = \(\left(\frac{-5}{2}\right)^2\)

\(=\frac{\left(-5\right)^2}{2^2}=\frac{25}{4}\)