*ĐKXĐ: \(x\ge0\)

Ta có: \(x=2\sqrt{x}\Leftrightarrow x-2\sqrt{x}=0\Leftrightarrow\sqrt{x}\left(\sqrt{x}-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x}=0\\\sqrt{x}-2=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=0\\\sqrt{x}=2\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\) (tm)

*Ta có: \(x^2=3\Leftrightarrow x^2-3=0\Leftrightarrow\left(x-\sqrt{3}\right)\left(x+\sqrt{3}=0\right)\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\sqrt{3}=0\\x+\sqrt{3}=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=\sqrt{3}\\x=-\sqrt{3}\end{matrix}\right.\)

*Ta có: \(x^2=15\Leftrightarrow x^2-15=0\Leftrightarrow\left(x-\sqrt{15}\right)\left(x+\sqrt{15}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\sqrt{15}=0\\x+\sqrt{15}=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=\sqrt{15}\\x=-\sqrt{15}\end{matrix}\right.\)

x : (-9/2) = -4/25

            x=-4/25 . (-9/2)

           x= 18/25

 Vậy x=18/25

x=-4*-9/

x=18/25

x=o,72

vậy...

|x+1| mũ 3 = -125

= |x+1| = - 125

= x = -125-1                   hoặc                       = x = -125 - ( -1 )

= x = -126                      hoặc                        = x = -124

Đk : `x > 0`

\(|-x+1|^3 = -125\)

Ta có : \(|-x+1|^3 > 0\)

Mà : \(-125 < 0\)

`=>x` không có giá trị nào thõa mãn

`=> x \in ∅`