ab x 7 = abc
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\(A=\left(x^2+\left(a+b\right)x+ab\right)\left(x+c\right)=x^3+\left(a+b+c\right)x^2+\left(ab+bc+ac\right)x+abc\)
\(A=x^3+6x^2-7x-60\)
Nếu rút gọn thành nhân tử thì:
\(A=x^3-3x^2+9x^2-27x+20x-60=x^2\left(x-3\right)+9x\left(x-3\right)+20\left(x-3\right)\)
\(=\left(x-3\right)\left(x^2+9x+20\right)=\left(x-3\right)\left(x^2+4x+5x+20\right)=\left(x-3\right)\left[x\left(x+4\right)+5\left(x+4\right)\right]\)
\(A=\left(x-3\right)\left(x+4\right)\left(x+5\right)\).
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pé pun
a﴿ ab x 101 = ab x ﴾100 + 1﴿
= ab x 100 + ab x 1
= ab00 + ab
= abab
b﴿ abc x 7 x 11 x 13
= abc x 1001
= abc x ﴾1000 + 1﴿
= abc x 1000 + abc x 1
= abc000 + abc
= abcabc
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ab x9 = ababababababababab
bc x 7 = abcabcabcabcabcabcabc
hok tốt nha !!
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\(\left(x+a\right)\left(x+b\right)\left(x+c\right)\)
\(=x^3+ax^2+bx^2+cx^2+abx+acx+bcx+abc\)
\(=x^3+x^2\left(a+b+c\right)+x\left(ab+ac+bc\right)+abc\)
\(=x^3+6x^2-7x-60\)