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\(\frac{20,2\times5,1-30,3\times3,4+14,58}{14,58\times460+7,29\times540\times2}\)
\(=\frac{10,1\times2\times5,1-10,1\times3\times3,4+14,58}{14,58\times460+14,58\times540}\)
\(=\frac{10,1\times\left(2\times5,1-3\times3,4\right)+14,58}{14,58\times\left(460+540\right)}\)
\(=\frac{10,1\times0+14,58}{14,58\times1000}\)
\(=\frac{14,58}{14580}\)\(=\frac{1458}{1458000}\)\(=\frac{1}{1000}\)
A = \(\dfrac{20,2\times5,1-30,3\times3,4+14,58}{14,58\times460+7,29\times540\times2}\)
A = \(\dfrac{10,1\times2\times5,1-10,1\times3\times3,4+14,58}{14,5\times460+(7,29\times2)\times540}\)
A = \(\dfrac{10,1\times\left(2\times5,1-3\times3,4\right)+14,58}{14,58\times460+14,58\times540}\)
A = \(\dfrac{10,1\times\left(10,2-10,2\right)+14,58}{14,58\times\left(460+540\right)}\)
A = \(\dfrac{10,1\times0+14,58}{14,58\times1000}\)
A = \(\dfrac{14,58}{14,58\times1000}\)
A = \(\dfrac{1}{1000}\)
A = 0,001
b)4y+(1/3+1/9+1/27)=56/81
4y+40/81=56/81
4y=56/81-40/81
4y=16/81
y=16/81:4
y=4/81
b) Tìm y:
( y + \(\frac{1}{3}\)) + ( y + \(\frac{1}{9}\)) + ( y + \(\frac{1}{27}\)) + ( y + \(\frac{1}{81}\)) = \(\frac{56}{81}\)
y + ( \(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)) = \(\frac{56}{81}\)
y + \(\frac{27+9+3+1}{81}\) = \(\frac{56}{81}\)
y + \(\frac{40}{81}\) = \(\frac{56}{81}\)
y = \(\frac{56}{81}-\frac{40}{81}\)
y = \(\frac{16}{81}\)
Tl roy, ủng hộ nha! :)