tìm y
5/6-y=3/5x15/18
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a, \(x\) - \(\dfrac{2}{7}\) = \(\dfrac{4}{5}\) \(\times\) \(\dfrac{15}{24}\)
\(x\) - \(\dfrac{2}{7}\) = \(\dfrac{1}{2}\)
\(x\) = \(\dfrac{1}{2}\) + \(\dfrac{2}{7}\)
\(x\) = \(\dfrac{11}{14}\)
b, \(x\): \(\dfrac{2}{7}\) = \(\dfrac{9}{8}\) - \(\dfrac{15}{6}\)
\(x\): \(\dfrac{2}{7}\) = - \(\dfrac{11}{8}\)
\(x\) = - \(\dfrac{11}{8}\) \(\times\) \(\dfrac{2}{7}\)
\(x\) = - \(\dfrac{11}{28}\)
\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}=\frac{2^{10}}{2^{10}}-\frac{2^5.\left(3.5\right)^3}{\left(2.3\right)^3.\left(2.5\right)^2}=1-\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}\)
\(=1-\frac{2^5.3^3.5^3}{\left(2^3.2^2\right).3^3.5^2}=1-\frac{2^5.3^3.5^3}{2^5.3^3.5^2}=\frac{1.1.5}{1.1.1}=5\)
y-2/7=4/5x15/24
y-2/7=4/5x5/8
y-2/7=1/2
y=1/2+2/7
y=7/14+4/14
y=11/14
\(\dfrac{8^5\cdot15^4}{2^{15}\cdot3^4\cdot5^3}=\dfrac{2^{15}\cdot3^4\cdot5^4}{2^{15}\cdot3^4\cdot5^3}=5\)
a) x= 10; y = 25
b) x + 2 y + 10 = 1 5 => ( x = 2).5 = ( y = 10).1=> 5.x + 10 = y + 10
=> 5.x = y mà y – 3.x = 2
Nên x = 1; y = 5
c) x = 20 ; y = 25
=>5/6-y=1/2
hay y=1/3
1/2