-5/12x2/11+-5/11x9/11+5/12
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NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
25 tháng 5 2022
A = \(\dfrac{-5}{12}\)x\(\dfrac{2}{11}\)+\(\dfrac{-5}{12}\)x\(\dfrac{9}{11}\)+\(\dfrac{5}{12}\)
A= \(\dfrac{-5}{12}\)(\(\dfrac{2}{11}\)+\(\dfrac{9}{11}\)-1)
A = 0
28 tháng 7 2015
a) (137x25-25x37):10
=25x(137-37):10
=25x100:10
=2500:10
=250
b) 2/7x21/4-2/7:13/4
=2/7x21/4-2/7x4/13
=2/7x(21/4-4/13)
=2/7x257/52
=257/182
c)(124x237+152):(870+235x122)
=(29388+152):(870+28670)
=29540:29540
=1
28 tháng 7 2015
a) (137 x 25 - 25 x 37 ) : 10 = (25 x (137 - 37) ) : 10
= (25 x 100) : 10
= 2500 : 10
= 250
28 tháng 7 2015
a)=(3425-925):10
=25200:10
=250
b)=3/2-8/91
=257/182
c)=(29388+152):(870+28670)
=29540:29540
=1
d)=1161+1539/72
=2700/72=75/2
e)=10/77+45/77x9/7
=10/77+405/539
=475/539
li ke cho mình nha Lam Le thi
DT
3
HN
30 tháng 4 2017
\(\dfrac{-5}{7}.\dfrac{2}{11}-\dfrac{5}{11}.\dfrac{9}{7}-2\dfrac{5}{7}\)
\(=\dfrac{-2}{7}.\dfrac{5}{11}-\dfrac{5}{11}.\dfrac{9}{7}-\dfrac{19}{7}\)
\(=\dfrac{5}{11}.\left(\dfrac{-2}{7}-\dfrac{9}{7}\right)-\dfrac{19}{7}\)
\(=\dfrac{5}{11}.\dfrac{-11}{7}-\dfrac{19}{7}\)
\(=\dfrac{-5}{7}-\dfrac{19}{7}\)
\(=\dfrac{-24}{7}\)
30 tháng 4 2017
\(\dfrac{-5}{7}.\dfrac{2}{11}-\dfrac{5}{11}.\dfrac{9}{7}-2\dfrac{5}{7}\)
\(=\dfrac{-2}{7}.\dfrac{5}{11}-\dfrac{5}{11}.\dfrac{9}{7}-\dfrac{19}{7}\)
\(=\dfrac{5}{7}\left(\dfrac{-2}{7}-\dfrac{9}{7}\right)-\dfrac{19}{7}\)
\(=\dfrac{5}{7}.\dfrac{-11}{7}-\dfrac{19}{7}\)
\(=\dfrac{5.\left(-11\right)}{11.7}-\dfrac{19}{7}\)
\(=\dfrac{-5.11}{11.7}-\dfrac{19}{7}\)
\(=\dfrac{-5}{7}-\dfrac{19}{7}\)
\(=\dfrac{-5-19}{7}\)
\(=\dfrac{\left(-5\right)+\left(-19\right)}{7}\)
\(=\dfrac{-24}{7}\)
DT
1
12 tháng 10 2017
\(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}\)
=\(\frac{5^{11}.7^{11}\left(7+1\right)}{5^{11}.7^{11}\left(5.7+9\right)}\)
= \(\frac{8}{35+9}\)
= \(\frac{8}{44}\)
= \(\frac{2}{11}\)
D
0
I
0
\(\dfrac{-5}{12}\times\dfrac{2}{11}+\dfrac{-5}{11}\times\dfrac{9}{11}+\dfrac{5}{12}\\ =\dfrac{5}{12}\times\left(1-\dfrac{2}{11}\right)+\dfrac{-5}{11}\times\dfrac{9}{11}\\ =\dfrac{5}{12}\times\dfrac{9}{11}+\dfrac{-5}{11}\times\dfrac{9}{11}\\ =\dfrac{9}{11}\times\left(\dfrac{5}{12}-\dfrac{5}{11}\right)\\ =\dfrac{9}{11}\times\dfrac{-5}{132}=-\dfrac{15}{484}\)