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![](https://rs.olm.vn/images/avt/0.png?1311)
bữa sau bạn nhớ giải thích nữa nha chớ mình không biết tại sao ra đáp án đó đâu
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\(c,\overline{735a2b}⋮̸2;⋮5\Rightarrow b=5\\ \Rightarrow\overline{735a25}⋮9\\ \Rightarrow7+3+5+a+2+5⋮9\\ \Rightarrow22+a⋮9\\ \Rightarrow a=5\\ \Rightarrow\overline{735a2b}=735525\\ b,\overline{5a27b}⋮2;⋮5\Rightarrow b=0\\ \Rightarrow\overline{5a270}⋮9\\ \Rightarrow5+a+2+7+0⋮9\\ \Rightarrow14+a⋮9\\ \Rightarrow a=4\\ \Rightarrow\overline{5a27b}=54270\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2022\times2005-2000\times2022+15\times2022-20\times2021\)
\(=2022\times\left(2005-2000+15\right)-20\times2021\)
\(=2022\times20-20\times2021\)
\(=20\times\left(2022-2021\right)\)
\(=20\times1\)
\(=20\)
a, 2022 \(\times\) 2005 - 2000 \(\times\) 2022 + 15 \(\times\) 2022 - 20 \(\times\) 2021
= (2022 \(\times\) 2005 - 2000 \(\times\) 2022 + 15 \(\times\) 2022 )- 20 \(\times\) 2021
= 2022 \(\times\) (2005 - 2000 + 15) - 20 \(\times\) 2021
= 2022 \(\times\) (5 +15) - 20 \(\times\) 2021
= 2022 \(\times\) 20 - 20 \(\times\) 2021
= 20 \(\times\) (2022 - 2021)
= 20 \(\times\) 1
= 20
![](https://rs.olm.vn/images/avt/0.png?1311)
She went to the supermarket yesterday.
We didn't go to school last week.
9. She went to the supermarket yesterday.
10. We didn't go to school last week.
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\(P=\left(\dfrac{x^2+1}{x^2-9}-\dfrac{x}{x+3}+\dfrac{5}{3-x}\right):\left(\dfrac{2x+10}{x+3}-1\right)\)
\(=\left(\dfrac{x^2+1}{\left(x-3\right)\left(x+3\right)}-\dfrac{x\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}-\dfrac{5\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\right):\left(\dfrac{2x+10}{x+3}-\dfrac{x+3}{x+3}\right)\)
\(=\left(\dfrac{x^2+1-x^2+3x-5x-15}{\left(x-3\right)\left(x+3\right)}\right):\left(\dfrac{2x+10-x-3}{x+3}\right)\)
\(=\left(\dfrac{-2x-14}{\left(x-3\right)\left(x+3\right)}\right):\left(\dfrac{x+7}{x+3}\right)\)
\(=\dfrac{-2\left(x+7\right)}{\left(x-3\right)\left(x+3\right)}.\dfrac{x+3}{x+7}\)
\(=\dfrac{-2}{x-3}\)
đk : x khác -3 ; 3 ; -7
\(P=\left(\dfrac{x^2+1+x\left(x-3\right)+5x+15}{x^2-9}\right):\left(\dfrac{2x+10-x-3}{x+3}\right)\)
\(=\dfrac{2x^2+1+2x+15}{x^2-9}:\dfrac{x+7}{x+3}=\dfrac{2x^2+2x+16}{\left(x-3\right)\left(x+7\right)}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
6, \(\Rightarrow-2\left(x-3\right)-8=5\left(x+2\right)\Leftrightarrow-2x-2=5x+10\)
\(\Leftrightarrow7x=-12\Leftrightarrow x=-\dfrac{12}{7}\)
7, \(\Rightarrow6\left(2x+1\right)-5\left(x+6\right)=5-4x\Leftrightarrow7x-24=5-4x\)
\(\Leftrightarrow11x=29\Leftrightarrow x=\dfrac{29}{11}\)
8, \(\Rightarrow35-15x-10-2x=10\Leftrightarrow25-17x=10\Leftrightarrow x=\dfrac{15}{17}\)
6: \(\Leftrightarrow-2\left(x-3\right)-8=5x+10\)
=>5x+10=-2x+6-8
=>5x+10=-2x-2
=>7x=-12
hay x=-12/7
7: \(\Leftrightarrow6\left(2x+1\right)-5\left(x+6\right)=5-4x\)
=>12x+6-5x-30-5+4x=0
=>11x-29=0
hay x=29/11
8: \(\Leftrightarrow5\left(7-3x\right)-2\left(x+5\right)=10\)
=>35-15x-2x-10=10
=>-17x=-15
hay x=15/17
Trung bình mỗi xe chở được:
\(\dfrac{14\cdot378+12\cdot4276}{26}=2177\left(kg\right)\)
2177