4/6x1/5+4/6x3/5+2/6x4/5 tính bằng cách thuận tiện
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\(\dfrac{5}{6}\times3+\dfrac{20}{6}\times2-1:\dfrac{6}{5}\)
\(=\dfrac{5}{6}\times3-\dfrac{5}{6}+\dfrac{20}{6}\times2\)
\(=\dfrac{5}{6}\times\left(3-1\right)+\dfrac{20}{6}\times2\)
\(=\dfrac{5}{6}\times2+\dfrac{20}{6}\times2\)
\(=\left(\dfrac{5}{6}+\dfrac{20}{6}\right)\times2\)
\(=\dfrac{25}{6}\times2\)
\(=\dfrac{25}{3}\)
#DatNe
\(\dfrac{5}{6}\) \(\times\) 3 + \(\dfrac{20}{6}\) \(\times\) 2 - 1 : \(\dfrac{6}{5}\)
= \(\dfrac{5}{6}\) \(\times\) 3 + \(\dfrac{20}{6}\) \(\times\) 2 - \(\dfrac{5}{6}\)
= \(\dfrac{5}{6}\) \(\times\) 3 + \(\dfrac{5}{6}\) \(\times\) 8 - \(\dfrac{5}{6}\) \(\times\)1
= \(\dfrac{5}{6}\) \(\times\) ( 3 + 8 - 1)
= \(\dfrac{5}{6}\) \(\times\)10
= \(\dfrac{25}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`4/6 xx 1/5 + 4/6 xx 3/5 + 2/6 xx 4/5`
`= 4/6 xx (1/5 + 3/5) + 2/6 xx 4/5`
`= 4/6 xx 4/5 + 2/6 xx 4/5`
`= (4/6 +2/6) xx 4/5`
`= 6/6 xx 4/5`
`=1 xx 4/5`
`=4/5`
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{1}{4}+\dfrac{2}{5}+\dfrac{3}{4}+\dfrac{3}{5}\)
\(=\left(\dfrac{1}{4}+\dfrac{3}{4}\right)+\left(\dfrac{2}{5}+\dfrac{3}{5}\right)\)
\(=1+1\)
\(=2\)
#Sahara |
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{4}+\frac{2}{5}+\frac{1}{4}+\frac{3}{5}\)
\(\Leftrightarrow\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)\)
\(=1+1\)
\(=2\)
\(\frac{3}{4}+\frac{2}{5}+\frac{1}{4}+\frac{3}{5}.\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)\)
\(=\frac{4}{4}+\frac{5}{5}\)
\(=1+1\)
\(=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
`2/5 xx 4/7 + 3/5 xx 4/7`
`= 4/7 xx (2/5 + 3/5)`
`= 4/7 xx 1`
`= 4/7`
![](https://rs.olm.vn/images/avt/0.png?1311)
5/7 - 2/5 x 4/6
= 5/7 - 2/5 x 2/3
= 5/2 x 2/7 - 2/5 x 2/3
= 5/2 x 2/7 + 5/2 x 2/3
= 5/2 x 4/21
= 10/21
5/7 - 2/5 x4/6
= 5/7 - 8/30
= 5/7 - 4/15
= (75- 28)/ 105
= 47/105
4/6x1/5+4/6x3/5+2/6x4/5
=4/6.(1/5+3/5)+2/6.4/5
=4/6.4/5+2/6.4/5
=4/5.(4/6+2/6)
=4/5.6/6
=4/5.1 = 4/5