Giúp mk vớiiiiii
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,=\left(2\sqrt{6}-4\sqrt{3}\right)\sqrt{6}+12\sqrt{2}=12-12\sqrt{2}+12\sqrt{2}=12\\ b,=\dfrac{6\left(3-\sqrt{3}\right)}{6}+\sqrt{3}=3-\sqrt{3}+\sqrt{3}=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(M=6\sqrt{2x}-\sqrt{2x}+2\sqrt{2x}-4\sqrt{2x}=3\sqrt{2x}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Nam used to go fishing when he was ten
This sweater was made by mu aunt for her son
We are taght grammar and writting by her
4.Nam often went fishing when he was ten
→ Nam used to go fishing when he was ten
5. My aunt made this sweater for her son
→ This sweater was made by my aunt for her son
6. She teaches us grammar and writing
→We are taught grammar and writing (by her)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(\Leftrightarrow\left[{}\begin{matrix}3x+2=4\\3x+2=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-2\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=\left(x+\dfrac{1}{x}\right)+\left(2y+\dfrac{8}{y}\right)+\left(x+y\right)\)
\(B\ge2\sqrt{\dfrac{x}{x}}+2\sqrt{\dfrac{16y}{y}}+3=13\)
\(B_{min}=13\) khi \(\left(x;y\right)=\left(1;2\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)