Tinh:A=2010^2010.(7^10:7^8-3.2^4-2^2018:2^2018)
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2010^2010 . ( 7^10 : 7^8 - 3 . 2^4 - 2^2010 : 2^2010 )
= 2010^2010 . ( 7^2 - 3 . 16 - 1 )
= 2010^2010 . ( 49 - 48 - 1 )
= 2010^2010 . ( 1 - 1 )
= 2010^2010 . 0
= 0
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dễ ẹc
20102010 .( 72 - 3.24 - 1) = 20102010. (49-48-1) = 20102010 .0 = 0
k tui nha nha nha
=20102010(72-3.24-1)
=20102010(49-3.16-1)
=20101010(49-48-1)
=20102010.0
=0
![](https://rs.olm.vn/images/avt/0.png?1311)
=1 nhưng mình ko biết trình bày bạn nào làm biết trình bày thì viết hô mình nha ?
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(Dấu . là dấu nhân)
a/\(\dfrac{2}{5}\cdot\dfrac{4}{3}-\dfrac{2}{5}:3\)
\(=\dfrac{2}{5}\cdot\dfrac{4}{3}-\dfrac{2}{5}\cdot\dfrac{1}{3}\)
\(=\dfrac{2}{5}\cdot\left(\dfrac{4}{3}-\dfrac{1}{3}\right)\)
\(=\dfrac{2}{5}\cdot1\)
\(=\dfrac{2}{5}\)
b/\(\dfrac{2010}{2018}:\dfrac{1}{2}+\dfrac{7}{2018}:\dfrac{1}{2}\)
\(=\left(\dfrac{2010}{2018}+\dfrac{7}{2018}\right):\dfrac{1}{2}\)
\(=\dfrac{2017}{2018}:\dfrac{1}{2}\)
\(=\dfrac{2017}{2018}\cdot2\)
\(=\dfrac{2017}{1009}\)
a, \(\dfrac{2}{5}\) \(\times\) \(\dfrac{4}{3}\) - \(\dfrac{2}{5}\) : 3
= \(\dfrac{2}{5}\) \(\times\) \(\dfrac{4}{3}\) - \(\dfrac{2}{5}\) \(\times\) \(\dfrac{1}{3}\)
= \(\dfrac{2}{5}\) \(\times\) ( \(\dfrac{4}{3}\) - \(\dfrac{1}{3}\))
= \(\dfrac{2}{5}\) \(\times\) 1
= \(\dfrac{2}{5}\)
b, \(\dfrac{2010}{2018}\) : \(\dfrac{1}{2}\) + \(\dfrac{7}{2018}\) : \(\dfrac{1}{2}\) + \(\dfrac{1}{2018}\) : \(\dfrac{1}{2}\)
= \(\dfrac{2010}{2018}\) \(\times\) \(\dfrac{2}{1}\) + \(\dfrac{7}{2018}\) \(\times\) \(\dfrac{2}{1}\) + \(\dfrac{1}{2018}\) \(\times\) \(\dfrac{2}{1}\)
= \(\dfrac{2}{1}\) \(\times\) ( \(\dfrac{2010}{2018}\) + \(\dfrac{7}{2018}\) + \(\dfrac{1}{2018}\))
= 2 \(\times\) \(\dfrac{2018}{2018}\)
= 2 \(\times\) 1
= 2
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(2.x - 15) . 11 = 11
2.x - 15 = 11 : 11
2.x - 15 = 1
2.x = 1 + 15
2.x = 16
x = 16 : 2 = 8
(x - 5) . (x - 7) = 0
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x-7=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=7\end{cases}}\)
(x - 2010) . 2009 = x - 2010
2009x - 4038090 = x - 2010
2009x - x = 4038090 - 2010
2008x = 4036080
x = 4036080 : 2008
x = 2010
(x - 11) .(x - 2018) = 0
\(\Rightarrow\orbr{\begin{cases}x-11=0\\x-2018=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=11\\x=2018\end{cases}}\)