(3*4*2^16)^2 / (11*2^13.4^11-16^9) = ?
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\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\dfrac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\dfrac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\dfrac{3^2.2^{36}}{11.2^{35}-2.2^{35}}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.9}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.3^2}\)
\(=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(3.4.2^16)^2/11.2^13.4^11-16^9
=3^2.4^2.(2^16)^2/11.2^13.(2^2)^11-(2^4)^9
=3^2.(2^2)^2.2^32/11.2^13.2^12-2^36
=3^2.2^4.2^32/11.2^13.2^12-2^36
=3^2.2^32+4/11.2^13+12-2^36
=3^2.2^36/11.2^35-2^36
=3^2.2^35.2/11.2^35-2^35.2
=3^2.2^35.2/2^35.(11-2)
=3^2.2^35.2/2^35.9
=3^2.2/9
=9.2/9
=2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{\left(2.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{2^2.4^2.\left(2^{16}\right)^2}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{2^2.2^4.2^{32}}{11.2^{35}-2^{36}}\)
\(=\frac{2^{38}}{2^{35}.\left(11-2\right)}\)
\(=\frac{2^{35}.2^3}{2^{35}.9}=\frac{2^3}{9}=\frac{8}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
bạn sai rồi
Oh
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.3^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2}{9}=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.\left(2^2\right)^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2}{2}=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=\dfrac{5^4\left(75+175\right)}{5^6\cdot4-5^4\cdot5^2\cdot3}=\dfrac{5^4\cdot250}{5^6}=10\)
b: \(=\dfrac{3^2\cdot5^2\cdot2^6}{2^3\cdot3^2}=\dfrac{5^2\cdot2^3}{1}=25\cdot8=200\)
c: \(=\dfrac{\left(3\cdot2^{18}\right)^2}{11\cdot2^{13}\cdot2^{22}-2^{36}}\)
\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{35}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\left(11-2\right)}=2\)
d: \(=12\left(194+437+369\right)=12000\)
e: \(=A\cdot\left(91-91\right)=0\)
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