Tìm x. Giúp mình với a) |x|+7/4=19/8 b) |x|-4/9=2/3. c) 8/3-|x| =-1/2\(\frac{ }{ }\)
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a) 3 x X x 2/3 = 4/5
3.x=6/5
x=2/5
b) 3,94 x 18,24 + 18,24 x 3,72 + 18,24 x 2,34
=18,24(3,94+3,72+2,34)
=18,24.10
=182,4
d) 8/19 x 2/7 + 8/19 x 1/7 + 8/19 x 4/7
=8/19(2/7+1/7+4/7)
=8/19.1
=8/19
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 3/8 . x = 9/8 - 1
3/8 . x = 1/8
x = 1/8 : 3/8
x = 1/3
b) 4/5 . x = 7/5 - 1/5
4/5 . x = 6/5
x = 6/5 : 4/5
x = 3/2
c) 12/7 : x + 2/3 = 7/5
12/7 : x = 7/5 - 2/3
12/7 : x = 11/15
x = 12/7 : 11/15
x = 180/77
d) 3.(x + 7) - 15 = 27
3.(x + 7) = 27 + 15
3.(x + 7) = 42
x + 7 = 42 : 3
x + 7 = 14
x = 14 - 7
x = 7
a) \(\dfrac{3}{8}x=\dfrac{9}{8}-1\)
\(\Rightarrow\dfrac{3}{8}x=\dfrac{1}{8}\)
\(\Rightarrow x=\dfrac{1}{8}:\dfrac{3}{8}=\dfrac{1}{3}\)
b) \(\dfrac{4}{5}x=\dfrac{7}{5}-\dfrac{1}{5}\)
\(\Rightarrow\dfrac{4}{5}x=\dfrac{6}{5}\)
\(\Rightarrow x=\dfrac{6}{5}:\dfrac{4}{5}=\dfrac{3}{2}\)
c) \(\dfrac{12}{7}:x+\dfrac{2}{3}=\dfrac{7}{5}\)
\(\Rightarrow\dfrac{12}{7}:x=\dfrac{7}{5}-\dfrac{2}{3}\)
\(\Rightarrow\dfrac{12}{7}:x=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{12}{7}:\dfrac{11}{15}=\dfrac{180}{77}\)
d) \(3\left(x+7\right)-15=27\)
\(\Leftrightarrow3\left(x+7\right)=42\)
\(\Leftrightarrow x+7=14\Leftrightarrow x=7\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A = ( -4/5 + 4/3 ) + (-5/4 + 14/5) - 7/3
= 8/15 + 31/20 - 7/3
= 25/12 - 7/3
= -1/4
B = 8/3 x 2/5 x 3/8 x 10x 19/92
= 16/15 x 15/4 x 19/92
= 4x19/92
= 19/23
a.
\(\left|x\right|+\frac{7}{4}=\frac{19}{8}\)
\(\left|x\right|=\frac{19}{8}-\frac{7}{4}\)
\(\left|x\right|=\frac{19-14}{8}\)
\(\left|x\right|=\frac{5}{8}\)
\(x=\pm\frac{5}{8}\)
Vậy \(x=\frac{5}{8}\) hoặc \(x=-\frac{5}{8}\)
b.
\(\left|x\right|-\frac{4}{9}=\frac{2}{3}\)
\(\left|x\right|=\frac{2}{3}+\frac{4}{9}\)
\(\left|x\right|=\frac{6+4}{9}\)
\(\left|x\right|=\frac{10}{9}\)
\(x=\pm\frac{10}{9}\)
Vậy \(x=\frac{10}{9}\) hoặc \(x=-\frac{10}{9}\)
c.
\(\frac{8}{3}-\left|x\right|=-\frac{1}{2}\)
\(\left|x\right|=\frac{8}{3}+\frac{1}{2}\)
\(\left|x\right|=\frac{16+3}{6}\)
\(\left|x\right|=\frac{19}{6}\)
\(x=\pm\frac{19}{6}\)
Vậy \(x=\frac{19}{6}\) hoặc \(x=-\frac{19}{6}\)
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