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Cái dấu chéo / là gì vậy bạn ( có phải la dấu GTTĐ | ko)
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\(x-\frac{3}{5}=\frac{4}{7}\) \(x+\frac{3}{5}=\frac{4}{3}\) \(-x-\frac{2}{7}=-\frac{8}{9}\)
\(x=\frac{4}{7}+\frac{3}{5}\) \(x=\frac{4}{3}-\frac{3}{5}\) \(-x=-\frac{8}{9}+\frac{2}{7}\)
\(x=\frac{41}{35}\) \(x=\frac{11}{15}\) \(-x=-\frac{38}{63}\)
\(x=\frac{38}{63}\)
\(\frac{7}{9}-x=\frac{1}{5}\)
\(x=\frac{7}{9}-\frac{1}{5}\)
\(x=\frac{26}{45}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x=-213:(1+2+3+4+...+100)<=>x=-213/100
b) x-x=-1/3-2/4 <=> 0= -5/6 (vô lý )
c) x=-0,8119408369
d) x= 0.0258907758
![](https://rs.olm.vn/images/avt/0.png?1311)
B1:
a)x=-3/5*9/25 =>x=-27/125
b)x=(4/7)6:(4/7)4 =>x=(4/7)2=16/49
c)(x/4)2=4:(x/2)
(x/4)2=8/x
x2/16=8/x2
x3=128
x=5,039
B2
M=23.10+22.10/23.4+22.11
=230+220/212+222
=230+28+222
=28(222+1+214)
=2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(6.8^{x-1}+8^{x+1}=6.8^{19}+8^{21}\)
\(\Rightarrow x-1+x+1=19+21\)
\(=2x=40\)
\(\Rightarrow x=20\)
b) \(4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(\Rightarrow x-1+x+2=6+9\)
\(\Rightarrow2x+1=15\)
\(\Rightarrow2x=14\)
\(\Rightarrow x=7\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(|x+4|=\frac{7}{3}\) \(\Rightarrow x+4=\pm\left(\frac{7}{3}\right)\)
TH1: \(x+4=\frac{7}{3}\)
\(x=\frac{7}{3}-4=-\frac{5}{3}\)
TH2: \(x+4=-\frac{7}{3}\)
\(x=-\frac{7}{3}-4=-\frac{19}{3}\)
a.
\(\left|x\right|+\frac{7}{4}=\frac{19}{8}\)
\(\left|x\right|=\frac{19}{8}-\frac{7}{4}\)
\(\left|x\right|=\frac{19-14}{8}\)
\(\left|x\right|=\frac{5}{8}\)
\(x=\pm\frac{5}{8}\)
Vậy \(x=\frac{5}{8}\) hoặc \(x=-\frac{5}{8}\)
b.
\(\left|x\right|-\frac{4}{9}=\frac{2}{3}\)
\(\left|x\right|=\frac{2}{3}+\frac{4}{9}\)
\(\left|x\right|=\frac{6+4}{9}\)
\(\left|x\right|=\frac{10}{9}\)
\(x=\pm\frac{10}{9}\)
Vậy \(x=\frac{10}{9}\) hoặc \(x=-\frac{10}{9}\)
c.
\(\frac{8}{3}-\left|x\right|=-\frac{1}{2}\)
\(\left|x\right|=\frac{8}{3}+\frac{1}{2}\)
\(\left|x\right|=\frac{16+3}{6}\)
\(\left|x\right|=\frac{19}{6}\)
\(x=\pm\frac{19}{6}\)
Vậy \(x=\frac{19}{6}\) hoặc \(x=-\frac{19}{6}\)
Chúc bạn học tốt![ok ok](/media/olmeditor/plugins/smiley/images/ok.png)
Cảm ơn bạn nhiều nhé.