\(\frac{34}{245}\) x \(\frac{323}{23}\)+ 467 = bao nhieu
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\(\frac{323}{34}+\frac{34}{345}\times84=17\frac{179}{230}\)
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\(=\left(\frac{x-1}{12}-1\right)+\left(\frac{2x-3}{23}-1\right)+\left(\frac{3x-5}{34}-1\right)+\left(\frac{4x-7}{45}-1\right)\)
\(=\frac{x-13}{12}+2.\frac{x-13}{23}+3.\frac{x-13}{34}+4.\frac{x-13}{45}\)
\(=\left(x-13\right)\left(\frac{1}{12}+\frac{2}{23}+\frac{3}{34}+\frac{4}{45}\right)\)
Đề thiếu phải không??? :))
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a: \(=\dfrac{17}{7}+\dfrac{2}{9}-\dfrac{10}{7}-\dfrac{5}{3}\cdot9=1+\dfrac{2}{9}-15=-14+\dfrac{2}{9}=-\dfrac{126}{9}+\dfrac{2}{9}=-\dfrac{124}{9}\)
b: \(=\dfrac{-11}{23}\left(\dfrac{6}{7}+\dfrac{8}{7}\right)-\dfrac{1}{23}=\dfrac{-22}{23}-\dfrac{1}{23}=-1\)
c: \(=\left(\dfrac{377}{-231}-\dfrac{123}{89}+\dfrac{34}{791}\right)\cdot\dfrac{4-3-1}{24}=0\)
d: \(=\dfrac{12}{7}\left(19+\dfrac{5}{8}-15-\dfrac{1}{4}\right)=\dfrac{12}{7}\cdot\dfrac{35}{8}=\dfrac{15}{2}\)
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\(\Leftrightarrow\frac{x-5}{325}-1+\frac{x-6}{324}-1=\frac{x-7}{323}-1+\frac{x-8}{322}-1\)
\(\Leftrightarrow\frac{x-330}{325}+\frac{x-330}{324}-\frac{x-330}{323}-\frac{x-330}{322}=0\)
\(\Leftrightarrow\left(x-330\right)\left(\frac{1}{325}+\frac{1}{324}-\frac{1}{323}-\frac{1}{322}\right)=0\)
Ma \(\frac{1}{325}+\frac{1}{324}-\frac{1}{323}-\frac{1}{322}\ne0\)
\(\Rightarrow x-330=0\)
\(\Rightarrow x=330\)
\(\frac{x-5}{325}+\frac{x-6}{324}=\frac{x-7}{323}+\frac{x-8}{322}\)
\(\Leftrightarrow\left[\frac{x-5}{325}-1\right]+\left[\frac{x-6}{324}-1\right]=\left[\frac{x-7}{323}-1\right]+\left[\frac{x-8}{322}-1\right]\)
\(\Leftrightarrow\frac{x-5-325}{325}+\frac{x-6-324}{324}=\frac{x-7-323}{323}+\frac{x-8-322}{322}\)
\(\Leftrightarrow\frac{x-330}{325}+\frac{x-330}{324}=\frac{x-330}{324}+\frac{x-330}{332}\)
\(\Leftrightarrow\frac{x-330}{325}+\frac{x-330}{324}=\frac{x-330}{324}+\frac{x-330}{332}=0\)
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