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\(x\) + (-31) - (42) = -45
\(x\) - (31 + 42) = -45
\(x\) - 73 = -45
\(x\) = -45 + 73
\(x\) = 28
305 - \(x\) + 14 = 48 + (\(x\) - 23)
(305 + 14) - \(x\) = (48 - 23) + \(x\)
319 - \(x\) = 25 + \(x\)
\(x\) + \(x\) = 319 - 25
2\(x\) = 294
\(x\) = 294 : 2
\(x\) = 147
\(x-43=\left(35-x\right)\) - 48
\(x\) - 43 = 35 - \(x\) - 48
\(x\) - 43 = - (48 - 35) - \(x\)
\(x\) - 43 = - 13 - \(x\)
\(x\) + \(x\) = -13 + 43
2\(x\) = 30
\(x\) = 30 : 2
\(x\) = 15
x + (-31) - 42 = -45
x - 73 = -45
x = -45 + 73
x = 28
-------
305 - x + 14 = 48 + (x - 23)
319 - x = 48 + x - 23
-x - x = 25 - 319
-2x = -294
x = -294 : (-2)
x = 147
--------
x - 43 = (35 - x) - 48
x = 35 - x - 48 + 43
x + x = 30
2x = 30
x = 30 : 2
x = 15
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x + ( -31 ) - ( - 42 ) = -45
=> x + ( -31 ) = -87
=> x = -56
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a) 2x - 31 + 42 = - 3x - 45
2x + 11 = - 3x - 45
2x + 3x = - 45 - 11
5x = - 56
x = - 56/5
b) - 25 + 2x = 15 + 17 - x
2x + x = 32 + 25
3x = 57
x = 19
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a, 41 x 42 x 43 x 44 x 45 x 46 x 47 x 48 x 49
Ta có : 44 x 45 có CSTC la` 0 vi` 4 x 5 = 2
=> 41 x 42 x 43 x ... x 49 co' CSTC la` 0
b, 69 x 31 x 35 x 37 - 24 x 17 x 35 x 14
= ( ...5) - ( ..0 ) = (...5)
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a. 9.(5-11) - 45
= 9.5 - 9.11 - 45
= 45 - 99 - 45
= -99
b. 35.(45 - 79) + 45.(79 - 35)
= 35.45 - 35.79 + 45.79 - 45.35
= 79 . (45 - 35)
= 79 . 10
= 790
c. 42 - 6.(11+7)
= 42 - 6.11 - 6.7
= 42 - 66 - 42
= -66
d. 17.(25 - 31) - 25.(17 - 31)
= 17.25 - 17.31 - 25.17 + 25.31
= 31.(25 - 17)
= 31 . 8
= 248
a)9×(5-11)-45
=9×5-9×11-45
=45-99-45
=45-45-99
=-99
b)35×(45-79)+45×(79-35)
=35×45-35×79+45×79-45×35
=(35×45-45×35)-35×79+45×79
=79×(-35+45)=79×10=790
d)17×(25-31)-25×(17-31)
=17×25-17×31-25×17-25×31
=(17×25-25×17)-17×31-25×31
=31×(-17-25)=32×(-42)=-1344
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2:
=>27:3^x=2*25-16-31=50-47=3
=>3^x=27/3=9
=>3^x=3^2
=>x=2
1:
b: \(=16\cdot55+16\cdot45-1\)
=16(55+45)-1
=1600-1
=1599
c: \(=\dfrac{1800}{49-\left[2\cdot\left(36-34\right)^3-5\right]}\)
\(=\dfrac{1800}{49-2\cdot2^3+5}=\dfrac{1800}{49-16+5}=\dfrac{1800}{38}\)=900/19
d: \(=\dfrac{5\cdot3^{11}\cdot2^{11}-3^{11}\cdot2^{11}}{2^{10}\cdot3^{10}\cdot2^2\cdot3+7\cdot2^{12}\cdot3^{12}}\)
\(=\dfrac{3^{11}\cdot2^{11}\left(5-1\right)}{2^{12}\cdot3^{11}\left(1+7\cdot3\right)}=\dfrac{1}{2}\cdot\dfrac{4}{1+21}=\dfrac{4}{22\cdot2}=\dfrac{1}{11}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 31 - ( 16 + 31 ) = x - ( 45 - 75 )
31 - 16 - 31 = x - 45 + 75
-16 = x + 30
x = -46
b) 9 - 45 = ( 8 - x ) - ( 35 + 8 )
-36 = 8 - x - 35 - 8
-36 = -x - 35
-x = -1
x = 1
x+ -31 + 42 =45
x+ 11. =45
x. = 34