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Question

x+27/343 + x+28/342 = x+121/249 + x+120/250

Nguyễn Huy Tú · Accepted Answer

$\dfrac{x+27}{343}+\dfrac{x+28}{342}=\dfrac{x+121}{249}+\dfrac{x+120}{250}$

$\Rightarrow\left(\dfrac{x+27}{343}+1\right)+\left(\dfrac{x+28}{342}+1\right)=\left(\dfrac{x+121}{249}+1\right)+\left(\dfrac{x+120}{250}+1\right)$

$\Rightarrow\dfrac{x+370}{343}+\dfrac{x+370}{342}-\dfrac{x+370}{249}-\dfrac{x+370}{250}=0$

$\Rightarrow\left(x+370\right)\left(\dfrac{1}{343}+\dfrac{1}{342}-\dfrac{1}{249}-\dfrac{1}{250}\right)=0$

Mà $\dfrac{1}{343}+\dfrac{1}{342}-\dfrac{1}{249}-\dfrac{1}{250}\ne0$

$\Rightarrow x+370=0\Rightarrow x=-370$

Vậy x = -370Câu trả lời: $\dfrac{x+27}{343}+\dfrac{x+28}{342}=\dfrac{x+121}{249}+\dfrac{x+120}{250}$

$\Rightarrow\left(\dfrac{x+27}{343}+1\right)+\left(\dfrac{x+28}{342}+1\right)=\left(\dfrac{x+121}{249}+1\right)+\left(\dfrac{x+120}{250}+1\right)$

$\Rightarrow\dfrac{x+370}{343}+\dfrac{x+370}{342}-\dfrac{x+370}{249}-\dfrac{x+370}{250}=0$

$\Rightarrow\left(x+370\right)\left(\dfrac{1}{343}+\dfrac{1}{342}-\dfrac{1}{249}-\dfrac{1}{250}\right)=0$

Mà $\dfrac{1}{343}+\dfrac{1}{342}-\dfrac{1}{249}-\dfrac{1}{250}\ne0$

$\Rightarrow x+370=0\Rightarrow x=-370$

Vậy x = -370

Trà My Phạm · Answer

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