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1) \(x+\dfrac{30}{100}x=-1,31\)
\(\Leftrightarrow x+\dfrac{3}{10}x=-\dfrac{131}{100}\)
\(\Leftrightarrow100x+30x=-131\)
\(\Leftrightarrow130x=-131\)
\(\Leftrightarrow x=-\dfrac{131}{130}\)
Vậy \(x=-\dfrac{131}{130}\)
b) \(\left(4,5-2x\right)\cdot\left(-1\dfrac{4}{7}\right)=\dfrac{11}{4}\)
\(\Leftrightarrow\left(\dfrac{9}{2}-2x\right)\cdot\left(-\dfrac{4}{7}\right)=\dfrac{11}{4}\)
\(\Leftrightarrow-\dfrac{18}{7}+\dfrac{8}{7}x=\dfrac{11}{4}\)
\(\Leftrightarrow-72+32x=77\)
\(\Leftrightarrow32x=77+72\)
\(\Leftrightarrow32x=149\)
\(\Leftrightarrow x=\dfrac{149}{32}\)
Vậy \(x=\dfrac{149}{32}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
x + \(\frac{3}{10}\)x - -1,31
x . ( \(1\)+ \(\frac{3}{10}\)) = -1,31
x . \(\frac{13}{10}\)= -1,31
x = -1,31 : \(\frac{13}{10}\)
x = \(\frac{-131}{130}\)
ai tốt bụng thì tk cho mk nha, mk đg âm điểm nè
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\(x+30\%x=-1,31\\ x+\dfrac{3}{10}x=-1\dfrac{31}{100}\\ x\cdot\left(1+\dfrac{3}{10}\right)=-\dfrac{131}{100}\\ x\cdot\dfrac{13}{10}=-\dfrac{131}{100}\\ x=-\dfrac{131}{100}:\dfrac{13}{10}=\dfrac{-131}{100}\cdot\dfrac{10}{13}=-\dfrac{131}{130}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: x(1+30%)=-1,31
⇒ \(\dfrac{13}{10}\)x =-1,31
⇒ x =-1,31 : \(\dfrac{13}{10}\)
⇒ x = -\(\dfrac{131}{130}\)
x + 30% x = -1,31
\(x+\dfrac{30}{100}x=-1,31\)
x+0,3x=-1,31
x.(0,3+1)=-1,31
x.1,3=-1,31
\(x=\dfrac{-1,31}{1,3}\)
\(x=-\dfrac{131}{130}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: x + 30 % x = -131/100
x ( 1 + 30%) = -131/100
x 13/10=-131/100
x = -131/100 ; 13/10
x = -131/130
b) )x+3/-15=1/3
x = 1/3 -3/-15
x= 8/15
=> x = \(\frac{8}{15}\)
Ta có: x + 30 % x = -131/100
x ( 1 + 30%) = -131/100
x 13/10=-131/100
x = -131/100 ; 13/10
x = -131/130
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x+\frac{3}{10}x=-\frac{131}{100}\)
\(x.\left(1+\frac{3}{10}\right)=-\frac{131}{100}\)
\(x.\frac{13}{10}=-\frac{131}{100}\)
\(x=-\frac{131}{100}:\frac{13}{10}\)
\(x=-\frac{131}{130}\)
\(x+\dfrac{30}{100}.x=-1,31\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ x.\left(1+\dfrac{30}{100}\right)=\dfrac{-131}{100}\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ x.\left(\dfrac{100}{100}+\dfrac{30}{100}\right)=\dfrac{-131}{100}\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ x.\dfrac{26}{20}=\dfrac{-131}{100}\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\\\ \\ x=\dfrac{-131}{100}:\dfrac{26}{20}=\dfrac{-131}{100}.\dfrac{20}{26}\\ \\ \\ \\ \\ \\ \\ \\ \\\\ \\ x=\dfrac{-131}{130}\)
coi chừng mình làm sai nhưng trinh bày mình đúng nhưng cẩn thận kết quả. nhé bye![hiuhiu hiuhiu](https://hoc24.vn/media/cke24/plugins/smiley/images/hiuhiu.png)
x+\(\dfrac{30}{100}\).x=-1,31
x+0,3.x=-1,31
x.(0,3+1)=-1,31
x.1,3=-1,31
x=-1,31:1,3
x=\(\dfrac{-131}{130}\)
Vậy x=\(\dfrac{-131}{130}\)
Chúc bạn học tốt nha![hihi hihi](https://hoc24.vn/media/cke24/plugins/smiley/images/hihi.png)