![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)3/4+1/1/4*2/2/3-(-1/2)^2:6/5
=3/4+5/4*8/3-1/4:6/5
=3/4+10/3-5/24=18/24+80/24-5/24=93/24=31/8
b)(x-1)^5=32=2^5
=>x-1=2
x=2+1
x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(\left(x+\dfrac{1}{4}\right)+\left(3x-4\right)+2\left(x-3\right)=1\)
=>\(x+\dfrac{1}{4}+3x-4+2x-6=1\)
=>\(6x-\dfrac{39}{4}=1\)
=>\(6x=1+\dfrac{39}{4}=\dfrac{43}{4}\)
=>\(x=\dfrac{43}{4}:6=\dfrac{43}{24}\)
b: \(2\left(x-3\right)=3\left(x+2\right)-x+1\)
=>\(2x-6=3x+6-x+1\)
=>2x-6=2x+7
=>-6=7(vô lý)
c: \(x\left(x+3\right)+x\left(x-2\right)=2x\left(x-1\right)\)
=>\(x^2+3x+x^2-2x=2x^2-2x\)
=>3x-2x=-2x
=>3x=0
=>x=0
d: \(\left(x-1\right)\cdot3x-2\left(x+2\right)-2x=x\left(x-1\right)\)
=>\(3x^2-3x-2x-4-2x=x^2-x\)
=>\(3x^2-7x-4-x^2+x=0\)
=>\(2x^2-6x-4=0\)
=>\(x^2-3x-2=0\)
=>\(x=\dfrac{3\pm\sqrt{17}}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
/x-2/>(=)0 với mọi x
=>5/x-2/>(=)0 với mọi x
=>5/x-2/ +2016 >(=) 2016 với mọi x
Dấu bằng xảy ra <=> x-2=0 =>x=2
vậy Amin =2016 <=> x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
| x + 1/2 | = 7/4
=> \(\hept{\begin{cases}x+\frac{1}{2}=\frac{7}{4}\\x+\frac{1}{2}=\frac{-7}{4}\end{cases}\Rightarrow\hept{\begin{cases}x=\frac{5}{4}\\x=\frac{-9}{4}\end{cases}}}\)
\(3-\left|x+\frac{1}{2}\right|=\frac{5}{4}\)
\(3-x+\frac{1}{2}=\frac{5}{4}\)
\(x+\frac{1}{2}=3-\frac{5}{4}\)
\(x+\frac{1}{2}=\frac{7}{4}\)
\(x=\frac{7}{4}-\frac{1}{2}\)
\(x=\frac{5}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{4}{\frac{2}{5}}:\left(-\frac{33}{10}\right)+x=-\frac{1}{\frac{5}{6}}\)
\(10:\left(-\frac{33}{10}\right)+x=-\frac{6}{5}\)
\(-\frac{100}{33}+x=-\frac{6}{5}\)
\(x=\frac{302}{165}\)