![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\left|x+\frac{4}{15}\right|=1,6\)
+) \(x+\frac{4}{15}=16\)
\(\Rightarrow x=\frac{236}{15}\)
+) \(x+\frac{4}{15}=-16\)
\(\Rightarrow x=-\frac{244}{15}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
|x + 4/15| - |-3,75| = -|- 2,15|
=> |x + 4/15| - 3,75 = 2,15
=> |x + 4/15| = 59/10
=> \(\orbr{\begin{cases}x+\frac{4}{15}=\frac{59}{10}\\x+\frac{4}{15}=-\frac{59}{10}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{169}{30}\\x=\frac{-185}{30}\end{cases}}\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\left|x+\frac{4}{15}\right|=1,6\)
\(\left|x+\frac{4}{15}\right|=\frac{8}{5}\)
\(\Rightarrow\hept{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=\frac{-8}{5}\end{cases}\Rightarrow\hept{\begin{cases}x=\frac{8}{5}-\frac{4}{15}=\frac{4}{3}\\x=\frac{-8}{5}-\frac{4}{15}=\frac{-28}{15}\end{cases}}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=-2,15+3,75\)
\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=\dfrac{8}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)
\(\Rightarrow\left|x+\dfrac{4}{15}\right|-3,75=-2,15\\ \Rightarrow\left|x+\dfrac{4}{15}\right|=1,6=\dfrac{8}{5}\\ \Rightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài làm :
Ta có :
\(\left|x+\frac{4}{15}\right|-\left|3,75\right|=-\left|2,15\right|\)
\(\Leftrightarrow\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\Leftrightarrow\left|x+\frac{4}{15}\right|=1,6\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{4}{15}=1,6\\x+\frac{4}{15}=-1,6\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=-\frac{28}{15}\end{cases}}\)
Vậy x=4/3 hoặc x=-28/15
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=1,6\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{15}=1,6\\x+\frac{4}{15}=-1,6\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=\frac{-28}{15}\end{cases}}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Leftrightarrow\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\Leftrightarrow\left|x+\frac{4}{15}\right|=\frac{8}{5}\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=-\frac{8}{5}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{4}{3}\\x=-\frac{28}{15}\end{cases}}\)
| x + \(\frac{4}{5}\)| - | - 3,75 | = - | - 2,15 |
=> | x + \(\frac{4}{5}\)| - 3,75 = - 2,15
=> | x + \(\frac{4}{5}\)| = 1,6
=> \(\orbr{\begin{cases}x+\frac{4}{5}=1,6\\x+\frac{4}{5}=-1,6\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{4}{5}\\x=-\frac{12}{5}\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, |x| - x = \(\frac{3}{4}\)
nếu x > hoặc = 0
suy ra |x| = x
|x| - x = 0
vậy x < 0
suy ra
|x| - ( -x ) = \(-\frac{3}{4}\)
|x| + x = \(-\frac{3}{4}\)
2 . x = \(-\frac{3}{4}\)
x = \(-\frac{3}{8}\)
nói rõ lại đề b hộ tôi vs
2 .
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Rightarrow\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=1,6=\frac{8}{5}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=\frac{-8}{5}\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=\frac{-28}{15}\end{array}\right.\)
Vậy \(\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=\frac{-28}{15}\end{array}\right.\)