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Bạn có thể viết dưới dạng phân số \(\frac{a}{b}\)kiểu này được không (ở thanh công thức ) đọc khó hiểu quá
Chúc bạn học tốt
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Lời giải:
Áp dụng TCDTSBN:
\(\frac{x-1}{2005}=\frac{3-y}{2000}=\frac{x-1+3-y}{2005+2000}=\frac{x-y+2}{4005}=\frac{4009+2}{4005}=\frac{4011}{4005}\)
\(\Rightarrow x-1=\frac{4011}{4005}.2005\Rightarrow x=\frac{536404}{267}\\ 3-y=\frac{4011}{4005}.2000\Rightarrow y\approx -2000\)
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Ta có : x-1/2005=3-y/2006=(x-1)+(3-y)/2005+2006=x-1+3-y/4011=(x-y)+(3-1)/4011
=4009+2/4011=4011/4011=1
Suy ra: x=(1x2005)+1=2006
y=3-(1x2006)=-2003
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ADTCDTSBN
có: \(\frac{x-1}{2005}=\frac{3-y}{2006}=\frac{x-1+3-y}{2005+2006}=\frac{\left(x-y\right)+\left(3-1\right)}{4011}=\frac{4009+2}{4011}=1.\)
=> (x-1)/2005 = 1 => x-1 = 2005 => x = 2006
(3-y)/2006 = 1 => 3-y = 2006 => y = -2003
KL:...\
Áp dụng dãy tỉ số bằng nhau ta có
\(\frac{x-1}{2005}=\frac{3-y}{2006}=\frac{x-1+3-y}{4011}=\frac{4009+2}{4011}=1\)=1
=>x-1=2005<=>x=2006
3-y=2006<=>y=-2003
Chúc học tốt!!!
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\(a,\dfrac{x}{7}=\dfrac{y}{3}=\dfrac{x-y}{7-3}=\dfrac{24}{4}=6\\ \Rightarrow x=6.7=42;y=6.3=18\\ b,\dfrac{x-1}{2005}=\dfrac{3-y}{2006}=\dfrac{x-1+3-y}{2005+2006}=\dfrac{4011}{4011}=1\\ \Rightarrow x-1=2005\Rightarrow x=2006\\ 3-y=2006\Rightarrow y=-2003\)
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Theo t,c dãy tỉ số bằng nhau ta có :
\(\dfrac{x-1}{2005}=\dfrac{3-y}{2006}=\dfrac{x-1+3-y}{2005+2006}=\dfrac{x-y+2}{4011}=\dfrac{4009+2}{4011}=1\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{x-1}{2005}=1\\\dfrac{3-y}{2006}=1\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=2006\\y=-2003\end{matrix}\right.\)
Vậy ...
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Từ: \(\frac{x-1}{2015}\)=\(\frac{3-y}{2016}\)=\(\frac{x-1+3-y}{2015+2016}\)=\(\frac{x-y+2}{4011}\)=\(\frac{4009+2}{4011}\)=\(\frac{4011}{4011}\)=1
Do:\(\frac{3-y}{2016}\) = 1 => x=2015
x =2015+ 1
x=2016
\(\frac{3-y}{2016}\)= 1 => y =2016
y=3- 2016
y= -2013
\(\frac{x-1}{2005}=\frac{3-y}{2006}=\frac{x-1+3-y}{2005+2006}=\frac{x-y+2}{4011}=\frac{4009+2}{2011}=1\)
=> x -1 = 2005 => x =2006
=> 2 -y = 2006 => y =3 -2006 = - 2003
x-1/2005=3-y/2006
áp dụng tc dãy ts = nhau ta có :
x-1/2005=3-y/2006=(x-1)+(3-y)/2005+2006=x-1+3-y/4011=x-y-1+3/4001=4009-1+3/4011=4011/4011=1
=>x-1/2005=1=>x-1=2005=>x=2006
=>3-y/2006=1=>3-y=2006=>y=-2003
vậy...