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![](https://rs.olm.vn/images/avt/0.png?1311)
+\(CH_4\) \(\underrightarrow{1500^oC}\) \(C_2H_2+H_2\)
\(C_2H_2+H_2\) \(\underrightarrow{Pd\text{/}PbCO_3,t^o}\) \(C_2H_4\)
\(C_2H_4\)\(+H_2O\) \(\underrightarrow{xt,t^o}\) \(C_2H_5OH\)
\(2C_2H_5OH+O_2\) \(\underrightarrow{men,t^o}\) \(2CH_3COOH\)
\(C_2H_5OH\) \(+CH_3COOH\) \(\underrightarrow{H_2SO_4,t^o}\) \(CH_3COOC_2H_5+H_2O\)
+\(C_2H_2+HCl\) \(\underrightarrow{xt,t^o}\) \(CH_2=CHCl\)
\(nCH_2=CHCl\) \(\underrightarrow{xt,p,t^o}\) \(\left(-CH_2-CHCl-\right)_n\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Hợp chất vô cơ | Hợp chất hữu cơ |
Nước,amoniac,natri clorua,stronti clorua,natri hipoclorit,canxi monodirua,mangan II oxit,axit cacbonic, cacbon monoxit, cacbon dioxit, iot,hidro | metan, etilen, axit axetic, etan, axetilen, etanol, metanol,Clorofom,nitrometan,propan, benzen, đimetyl ete, metoxietan,clotriflometan, glucozơ, nhựa PE, nhựa PVC. |
![](https://rs.olm.vn/images/avt/0.png?1311)
CaC2 + 2H2O → C2H2 + Ca(OH)2
C2H2 + H2 ---to---> C2H4
C2H4 + H2 ---to Ni---> C2H6
C2H6 + Cl2 ---ánh sáng---> C2H5Cl + HCl
CaC2 + 2H2O → C2H2 + Ca(OH)2
C2H2 + H2 → C2H4
C2H4 + H2 → C2H6
C2H6 + Cl2 → C2H5Cl + HCl
Cho 4,8g khí Metan tác dụng với khí Clo ở điều kiện thích hợp. Khối lượng Metyl clorua thu được là ?
![](https://rs.olm.vn/images/avt/0.png?1311)
\(n_{CH_4}=\dfrac{m}{M}=0,3\left(mol\right)\)
\(CH_4+Cl_2\rightarrow CH_3Cl+HCl\)
.0,3....................0,3...........
\(\Rightarrow m_{CH3Cl}=n.M=15,15\left(g\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
PTHH: \(CH_4+Cl_2\underrightarrow{a/s}CH_3Cl+HCl\)
Theo PTHH: \(n_{Cl_2}=n_{CH_3Cl}=n_{CH_4}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
\(\Rightarrow\left\{{}\begin{matrix}m_{CH_3Cl}=0,15\cdot50,5=7,575\left(g\right)\\V_{CH_4}=V_{Cl_2}=3,36\left(l\right)\end{matrix}\right.\)
Bài 2:
PTHH: \(CH_4+2O_2\underrightarrow{a/s}CO_2+2H_2O\)
Theo PTHH: \(\left\{{}\begin{matrix}n_{CO_2}=n_{CH_4}\\n_{O_2}=2n_{CH_4}\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}V_{CO_2}=V_{CH_4}=5,6\left(l\right)\\V_{CO_2}=2V_{CH_4}=11,2\left(l\right)\end{matrix}\right.\)
a,
\(C_4H_{10}\underrightarrow{^{to}}C_2H_4+C_2H_6\)
\(C_2H_6+Cl_2\underrightarrow{^{als}}C_2H_5Cl+HCl\)
\(2C_2H_5Cl+Na\underrightarrow{^{to}}C_4H_{10}+2NaCl\)
\(C_4H_{10}\underrightarrow{^{to}}CH_4+C_3H_6\)
\(CH_4+2Cl_2\rightarrow C+4HCl\)
b,
\(Al_4C_3+12HCl\rightarrow3CH_4+4AlCl_3\)
\(CH_4+Cl_2\underrightarrow{^{as}}CH_3Cl+HCl\)
\(2CH_3Cl+Na\underrightarrow{^{to}}C_2H_6+2NaCl\)
\(C_2H_6+Cl_2\underrightarrow{^{as}}C_2H_5Cl+HCl\)
a) - C4H10 -to-> C2H6 + C2H4
- C2H6 + Cl2 --> C2H5Cl + HCl
- 2C2H5Cl + Na --> C4H10 + 2NaCl
- C4H10 -to-> CH4 + C3H6
- CH4 --to--> C + 2H2
b) - Al4C3 + 12H2O --> 4Al(OH)3 + 3CH4
- CH4 + Cl2 --> CH3Cl + HCl
- 2CH3Cl + Na -to-> C2H6 + 2NaCl
- C2H6 + Cl2 --> C2H5Cl + HCl