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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1/
\(\left(1\right)4NH_3+5O_2\xrightarrow[pt]{t^0}4NO+6H_2O\)
\(\left(2\right)NO+\frac{1}{2}O_2\rightarrow NO_2\)
\(\left(3\right)4NH_3+3O_2\underrightarrow{t^0}2N_2+6H_2O\)
\(\left(4\right)N_2+O_2\rightarrow2NO\uparrow\)
2/
\(\left(1\right)2NH_4NO_3\underrightarrow{t^0}2N_2+O_2+4H_2O\)
\(\left(2\right)N_2+3H_2\underrightarrow{\leftarrow}2NH_3\)
\(\left(3\right)3NH_3+FeCl_3+3H_2O\rightarrow Fe\left(OH\right)_3+3NH_4Cl\)
\(\left(4\right)Fe\left(OH\right)_3+3HNO_3\rightarrow Fe\left(NO_3\right)_3+3H_2O\)
\(\left(5\right)4Fe\left(NO_3\right)_3\rightarrow2Fe_2O_3+12NO_2+3O_2\)
\(\left(6\right)2NO_2+\frac{1}{2}O_2+H_2O\rightarrow2HNO_3\)
\(\left(7\right)NaOH+HNO_3\rightarrow NaNO_3+H_2O\)
\(\left(8\right)2NaNO_3\rightarrow2NaNO_2+O_2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(N_2+3H_2\underrightarrow{t^o,p}2NH_3\)
\(4NH_3+5O_2\underrightarrow{t^o,xt}4NO+6H_2O\)
\(2NO+O_2\rightarrow2NO_2\)
\(4NO_2+O_2+2H_2O\rightarrow4HNO_3\)
\(Cu+4HNO_3\rightarrow Cu\left(NO_3\right)_2+2NO_2+2H_2O\)
\(2Cu\left(NO_3\right)_2\underrightarrow{t^o}2CuO+4NO_2+O_2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu 17:
\(1.\) Đặt CTHH là \(C_xH_yO_z\)
\(\%_O=100\%-40\%-6,67\%=53,33\%\\ \Rightarrow x:y:z=\dfrac{40}{12}:\dfrac{6,67}{1}:\dfrac{53,33}{16}=3,33:6,67:3,33=1:2:1\\ \Rightarrow CTDGN:\left(CH_2O\right)_n\)
\(2.\) Ta có \(M_{\left(CH_2O\right)_n}=2,143\cdot14\cdot2=60=30n\)
\(\Rightarrow n=2\)
Vậy \(CTHH_X:C_2H_4O_2\)
Câu 16:
\((1)2NH_3\xrightarrow{t^o,xt}3H_2+N_2\\ (2)N_2+O_2\buildrel{{t^o}}\over\rightleftharpoons2NO\\ (3)2NO+O_2\to 2NO_2\\ (4)4NO_2+O_2+2H_2O\to 4HNO_3\\ (5)10HNO_3+4Mg\to 4Mg(NO_3)_2+N_2O\uparrow +5H_2O\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án C
(1)NH3 + O2 NO + H2O
(2)NH3 + 3CuO 3Cu + 3H2O + N2
(3)NH4NO3 + NaOH NaNO3 + NH3 + H2O
(4) NH4Cl NH3 + HCl
![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án C
(1)NH3 + O2 → 850 ° , Pt NO + H2O
(2)NH3 + 3CuO → t ° 3Cu + 3H2O + N2
(3)NH4NO3 + NaOH → t ° NaNO3 + NH3 + H2O
(4) NH4Cl → t ° NH3 + HCl
![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án C
(1)NH3 + O2 → 850 ° , Pt NO + H2O
(2)NH3 + 3CuO → t ° 3Cu + 3H2O + N2
(3)NH4NO3 + NaOH → t ° NaNO3 + NH3 + H2O
(4) NH4Cl → t ° NH3 + HCl
![](https://rs.olm.vn/images/avt/0.png?1311)
NH4Cl \(\rightarrow\) NH3\(\rightarrow\)N2 \(\rightarrow\) NO \(\rightarrow\) NO2 \(\rightarrow\) HNO3 \(\rightarrow\) NaNO3 \(\rightarrow\) O2
NH4Cl+NaOH\(\rightarrow\)NaCl+NH3+H2O
2NH3+3Cl2\(\rightarrow\)N2+6HCl
N2+O2\(\rightarrow\)2NO (tia lửa điện)
NO+\(\frac{1}{2}\)O2\(\rightarrow\)NO2
NO2+H2O+\(\frac{3}{2}\)O2\(\rightarrow\)2HNO3
HNO3+NaOH\(\rightarrow\)NaNO3+H2O
NaNO3\(\rightarrow\)NaNO2+\(\frac{1}{2}\)O2 (nhiệt phân)
NH4NO2--->N2+2H2O
N2+O2---->2NO
2NO+O2--->2NO2
4NO2+O2+2H2O--->4HNO3
HNO3+NH3--->NH4NO3
NH4NO3+2NaOH--->NaNO3+NH3+H2O
NH3+HCl--->NH4Cl
N2+3H2--->2NH3
2NH3+5/2O2---->2NO+3H2O
2NO+O2--->2NO2
4NO2+O2+2H2O--->4HNO3
HNO3+NH3--->NH4NO3
NH4NO3+NaOH=---->NH3+H2O+NaNO3
2NH3---->N2+3H2
N2+6Na---->2Na3N
1. \(\text{NH4NO2 → 2H2O + N2 }\)
2.\(\text{N2 + O2 ↔ 2NO}\uparrow\)
3.\(\text{2NO + O2 → 2NO2}\uparrow\)
4.\(\text{H2O + 3NO2 → 2HNO3 + NO}\uparrow\)
5.\(\text{HNO3 + NH3 → NH4NO3}\)
6.\(\text{NaOH + NH4NO3 → H2O + NaNO3 + NH3}\uparrow\)
7.\(\text{3Cl2 + 2NH3 → 6HCl + N2}\uparrow\)
8.\(\text{HCl + NH3 → NH4Cl}\)