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\(\dfrac{9}{25}=\left(\dfrac{3}{5}\right)^2\)
\(\dfrac{8}{27}=\left(\dfrac{2}{3}\right)^3\)
\(\dfrac{-125}{64}=\left(-\dfrac{5}{4}\right)^3\)
\(0=0^2\)
\(-27=\left(-3\right)^3\)
\(\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{81}{125}=\dfrac{3^4}{5^3}\) ; \(-\dfrac{8}{27}=-\left(\dfrac{2}{3}\right)^3\)
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\(\begin{array}{l}0,49 = {\left( {0,7} \right)^2};\\\,\frac{1}{{32}} =\frac{1^5}{2^5}={\left( {\frac{1}{2}} \right)^5};\\\,\frac{{ - 8}}{{125}} =\frac{(-2)^3}{5^3}= {\left( {\frac{{ - 2}}{5}} \right)^3};\end{array}\)
\(\frac{{16}}{{81}} =\frac{4^2}{9^2}= {\left( {\frac{4}{9}} \right)^2} (hoặc \,\frac{{16}}{{81}} =\frac{2^4}{3^4}= {\left( {\frac{2}{3}} \right)^4});\\\,\frac{{121}}{{169}} =\frac{11^2}{13^2}= {\left( {\frac{{11}}{{13}}} \right)^2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{81}{125}\) viết dưới dạng luỹ thừa là : \(\frac{3^4}{5^3}\)
\(-\frac{8}{27}\) viết dưới dạng luỹ thừa là : \(-\frac{2^3}{3^3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{81}{125}-\dfrac{8}{27}=\dfrac{3^4}{5^3}-\dfrac{2^3}{3^3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
-8/27 = (-2/3)3 nha còn cái kia mình cụng ko bít đâu mình cũng đang hỏi
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{81}{125}=\dfrac{3^4}{5^3}\)
\(\dfrac{-8}{27}=\dfrac{\left(-2\right)^3}{3^3}=\left(\dfrac{-2}{3}\right)^3\)
Ta có:
\(\dfrac{81}{125}=\dfrac{3^4}{5^4}=\left(\dfrac{3}{5}\right)^4\)
\(-\dfrac{8}{27}=-\dfrac{2^3}{3^3}=\left(-\dfrac{2}{3}\right)^3\)