Câu hỏi của Nguyễn Thùy Chi

Question

Từ CH4 lập sơ đồ điều chế caosubuna, benzen, polietilen

Lê Ng Hải Anh · Accepted Answer

(1) $CH_4\rightarrow C_2H_2\rightarrow C_4H_4\rightarrow C_4H_6\rightarrow$ cao su Buna.$2CH_4\xrightarrow[lln]{^{1500^oC}}C_2H_2+3H_2$$2C_2H_2\underrightarrow{^{t^o,xt,p}}C_4H_4$$CH\equiv C-CH=CH_2+H_2\underrightarrow{^{t^o,Pd}}CH_2=CH-CH=CH_2$$nCH_2=CH-CH-CH_2\underrightarrow{^{t^o,p,xt}}\left(-CH_2-CH-CH-CH_2-\right)_n$ (2) $CH_4\rightarrow C_2H_2\rightarrow C_6H_6$$2CH_4\xrightarrow[lln]{^{1500^oC}}C_2H_2+3H_2$$3C_2H_2\underrightarrow{^{t^o,p,xt}}C_6H_6$(3) $CH_4\rightarrow C_2H_2\rightarrow C_2H_4\rightarrow$ polietilen.$2CH_4\xrightarrow[lln]{^{1500^oC}}C_2H_2+3H_2$$C_2H_2+H_2\underrightarrow{^{t^o,Pd}}C_2H_4$$nCH_2=CH_2\underrightarrow{t^o,p,xt}\left(-CH_2-CH_2-\right)_n$Câu trả lời: (1) $CH_4\rightarrow C_2H_2\rightarrow C_4H_4\rightarrow C_4H_6\rightarrow$ cao su Buna.$2CH_4\xrightarrow[lln]{^{1500^oC}}C_2H_2+3H_2$$2C_2H_2\underrightarrow{^{t^o,xt,p}}C_4H_4$$CH\equiv C-CH=CH_2+H_2\underrightarrow{^{t^o,Pd}}CH_2=CH-CH=CH_2$$nCH_2=CH-CH-CH_2\underrightarrow{^{t^o,p,xt}}\left(-CH_2-CH-CH-CH_2-\right)_n$ (2) $CH_4\rightarrow C_2H_2\rightarrow C_6H_6$$2CH_4\xrightarrow[lln]{^{1500^oC}}C_2H_2+3H_2$$3C_2H_2\underrightarrow{^{t^o,p,xt}}C_6H_6$(3) $CH_4\rightarrow C_2H_2\rightarrow C_2H_4\rightarrow$ polietilen.$2CH_4\xrightarrow[lln]{^{1500^oC}}C_2H_2+3H_2$$C_2H_2+H_2\underrightarrow{^{t^o,Pd}}C_2H_4$$nCH_2=CH_2\underrightarrow{t^o,p,xt}\left(-CH_2-CH_2-\right)_n$

NGUYỄN CHÍ tiến · Answer

(1) CH4→C2H2→C4H4→C4H6→��4→�2�2→�4�4→�4�6→ cao su Buna.2CH41500oC−−−→llnC2H2+3H22��4→���1500���2�2+3�22C2H2to,xt,p−−−→C4H42�2�2��,��,�→�4�4CH≡C−CH=CH2+H2to,Pd−−→CH2=CH−CH=CH2��≡�−��=��2+�2��,��→��2=��−��=��2nCH2=CH−CH−CH2to,p,xt−−−→(−CH2−CH−CH−CH2−)n���2=��−��−��2��,�,��→(−��2−��−��−��2−)� (2) CH4→C2H2→C6H6��4→�2�2→�6�62CH41500oC−−−→llnC2H2+3H22��4→���1500���2�2+3�23C2H2to,p,xt−−−→C6H63�2�2��,�,��→�6�6(3) CH4→C2H2→C2H4→��4→�2�2→�2�4→ polietilen.2CH41500oC−−−→llnC2H2+3H22��4→���1500���2�2+3�2C2H2+H2to,Pd−−→C2H4�2�2+�2��,��→�2�4nCH2=CH2to,p,xt−−−−−→(−CH2−CH2−)nCâu trả lời: (1) CH4→C2H2→C4H4→C4H6→��4→�2�2→�4�4→�4�6→ cao su Buna.2CH41500oC−−−→llnC2H2+3H22��4→���1500���2�2+3�22C2H2to,xt,p−−−→C4H42�2�2��,��,�→�4�4CH≡C−CH=CH2+H2to,Pd−−→CH2=CH−CH=CH2��≡�−��=��2+�2��,��→��2=��−��=��2nCH2=CH−CH−CH2to,p,xt−−−→(−CH2−CH−CH−CH2−)n���2=��−��−��2��,�,��→(−��2−��−��−��2−)� (2) CH4→C2H2→C6H6��4→�2�2→�6�62CH41500oC−−−→llnC2H2+3H22��4→���1500���2�2+3�23C2H2to,p,xt−−−→C6H63�2�2��,�,��→�6�6(3) CH4→C2H2→C2H4→��4→�2�2→�2�4→ polietilen.2CH41500oC−−−→llnC2H2+3H22��4→���1500���2�2+3�2C2H2+H2to,Pd−−→C2H4�2�2+�2��,��→�2�4nCH2=CH2to,p,xt−−−−−→(−CH2−CH2−)n

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