Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu hỏi của ✨♔♕ Saiko ♕♔✨ - Toán lớp 6 - Học toán với OnlineMath
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{2}.x-70\frac{10}{11}:\left(\frac{131313}{151515}+\frac{131313}{353535}+\frac{131313}{636363}+\frac{131313}{999999}=-5\right)\)
\(\frac{3}{2}.x-70\frac{10}{11}:\left(\frac{13}{15}+\frac{13}{35}+\frac{13}{63}+\frac{13}{99}\right)=-5\)
\(\frac{3}{2}.x-70\frac{10}{11}:\left[13\times\left(\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}\right)\right]=-5\)
\(\frac{3}{2}.x-70\frac{10}{11}:\left[13\times\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right)\right]=-5\)
\(\frac{3}{2}.x-70\frac{10}{11}:\left[13\times\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\right]=-5\)
\(\frac{3}{2}.x-70\frac{10}{11}:\left[13\times\left(\frac{1}{3}-\frac{1}{11}\right)\right]=-5\)
\(\frac{3}{2}.x-\frac{45}{2}=-5\)
\(\frac{3}{2}.x=\frac{35}{2}\)
\(x=\frac{35}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=70\cdot\left(\frac{131313}{565656}+\frac{131313}{727272}+\frac{131313}{909090}\right)\)
\(B=70\cdot\left(\frac{13}{56}+\frac{13}{72}+\frac{13}{90}\right)\)
\(B=70\cdot\left[13\cdot\left(\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\right)\right]\)
\(B=70\cdot\left[13\cdot\left(\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}\right)\right]\)
\(B=70\cdot\left[13\cdot\left(\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\right)\right]\)
\(B=70\cdot\left[13\cdot\left(\frac{1}{7}-\frac{1}{10}\right)\right]\)
\(B=70\cdot13\cdot\frac{3}{70}\)
\(B=70\cdot\frac{3}{70}\cdot13\)
\(B=3\cdot13\)
\(B=39\)
a) (-1)^a =1 với a chẵn, (-1)^a =-1 với a lẻ
\(A=\left(-1\right)^{1+2+3+4+..+2010+2011}=\left(-1\right)^{\frac{2011+1}{2}.2011}=\left(-1\right)^{1006.2011}=1\)
Vì 1006 là số chẵn => 1006.2011 là số chẵn
b) \(B=70.\left(\frac{13.10101}{56.10101}+\frac{13.10101}{72.10101}+\frac{13.10101}{90.10101}\right)=70.\left(\frac{13}{56}+\frac{13}{72}+\frac{13}{90}\right)=3.13=39\)
c) Áp dụng dãy tỉ số bằng nhau ta có:
\(\frac{2a}{3b}=\frac{3b}{4c}=\frac{4c}{5d}=\frac{5d}{2a}=\frac{2a+3b+4c+5d}{3b+4c+5d+2a}=1\)
=> C=4
=13881496.0970/1084876.05369