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Bài 1:
\(A=\frac{\frac{1}{12}-\frac{2}{9}-1}{\frac{5}{18}+\frac{-3}{4}-\frac{1}{9}}\)
\(A=\frac{\frac{1}{12}-\frac{2}{9}-\frac{18}{18}}{\frac{5}{18}+\frac{9}{12}-\frac{1}{9}}\)
\(A=\frac{1}{3}-\frac{18}{5}\)\(A=\frac{5}{15}-\frac{54}{15}\)
\(A=\frac{-49}{15}\)
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a, Câu hỏi của Nguyễn Ánh Ngân - Toán lớp 6 - Học toán với OnlineMath
b, Câu hỏi của Vũ Xuân Hiếu - Toán lớp 6 | Học trực tuyến
c)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}+\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{25}-\frac{4}{125}-\frac{4}{625}}\)
= \(1+\frac{3.\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}{4.\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}\)
= \(1+\frac{3}{4}\)
= \(\frac{4}{4}+\frac{3}{4}\)
= \(\frac{7}{4}\)
HỌC TỐT
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![](https://rs.olm.vn/images/avt/0.png?1311)
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\(\frac{\left(81,624:4\frac{4}{3}-4,505\right)+125\frac{3}{4}}{\left[\left(\left(\frac{11}{25}\right)^2:0,08+3,53\right)^2-\left(2,75\right)^2\right]:\frac{13}{25}}\)
\(=\frac{\left(\frac{10203}{125}.\frac{3}{16}-\frac{901}{200}\right)+\frac{503}{4}}{\left[\left(\frac{121}{625}.\frac{25}{2}+\frac{353}{100}\right)^2-\frac{121}{16}\right].\frac{25}{13}}\)
\(=\frac{\left(15,3045-\frac{901}{200}\right)+\frac{503}{4}}{\left(\frac{14161}{400}-\frac{121}{16}\right).\frac{25}{13}}\)
\(=\frac{136,5495}{\frac{696}{13}}\)
\(=2,550493534\)
\(\frac{\frac{125}{8}+\frac{125}{97}+\frac{125}{576}+\frac{250}{991}}{\frac{25}{8}+\frac{25}{97}+\frac{25}{576}+\frac{50}{991}}\)=\(\frac{250.\left(\frac{1}{8}+\frac{1}{97}+\frac{1}{576}+\frac{1}{991}\right)}{50.\left(\frac{1}{8}+\frac{1}{97}+\frac{1}{576}+\frac{1}{991}\right)}\)=\(\frac{250}{50}\)=5
Nhớ tick