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a, \(\left(\frac{2}{5}+\frac{3}{4}\right)^2=\left(\frac{8}{20}+\frac{15}{20}\right)^2=\left(\frac{23}{20}\right)^2=\frac{529}{400}\)
b, \(\left(\frac{5}{4}-\frac{1}{6}\right)^2=\left(\frac{30}{24}-\frac{4}{24}\right)^2=\left(\frac{13}{12}\right)^2=\frac{169}{144}\)
a)\(\left(\frac{2}{5}+\frac{3}{4}\right)^2=\left(\frac{8}{20}+\frac{15}{20}\right)^2=\left(\frac{23}{20}\right)^2=\frac{529}{400}\)
b)\(\left(\frac{5}{4}-\frac{1}{6}\right)^2=\left(\frac{15}{12}-\frac{2}{12}\right)^2=\left(\frac{13}{12}\right)^2=\frac{169}{144}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^3+\left(\dfrac{1}{5}\right)^4+5^4=8+\dfrac{1}{625}+625=\dfrac{5000+1+625^2}{625}=\dfrac{395626}{625}\)
\(Sửa:2^3+\left(\dfrac{1}{5}\right)^4\cdot5^4=8+\left(\dfrac{1}{5}\cdot5\right)^4=8+1=9\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
1. \(x:-\left(-\frac{1}{2}\right)=-\frac{1}{2}\)
⇒ \(x:\frac{1}{2}=-\frac{1}{2}\)
⇒ \(x=\left(-\frac{1}{2}\right).\frac{1}{2}\)
⇒ \(x=-\frac{1}{4}\)
Vậy \(x=-\frac{1}{4}.\)
3. \(\frac{16}{2^n}=2\)
⇒ \(2^n=16:2\)
⇒ \(2^n=8\)
⇒ \(2^n=2^3\)
⇒ \(n=3\)
Vậy \(n=3.\)
4. \(\frac{-3^n}{81}=-27\)
⇒ \(\left(-3\right)^n=\left(-27\right).81\)
⇒ \(\left(-3\right)^n=-2187\)
⇒ \(\left(-3\right)^n=\left(-3\right)^7\)
⇒ \(n=7\)
Vậy \(n=7.\)
Chúc bạn học tốt!
a) \(\frac{2}{5}+\frac{3}{4}=\frac{2\cdot4+3\cdot5}{20}=\frac{8+15}{20}=\frac{23}{20}\)
b) \(\frac{5}{4}-\frac{1}{6}=\frac{5\cdot3-2}{12}=\frac{15-2}{12}=\frac{13}{12}\)
a, \(\frac{2}{5}+\frac{3}{4}=\frac{8}{20}+\frac{15}{20}=\frac{23}{20}\)
b,\(\frac{5}{4}-\frac{1}{6}=\frac{30}{24}-\frac{4}{24}=\frac{26}{24}=\frac{13}{12}\)