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E = 5,5.(2 – 3,6) = 5,5.(-1,6) = -8,8
E = 5,5.(2 – 3,6) = 5,5.2 – 5,5.3,6 = 11 – 19,8 = -8,8
F = - 3,1.(3 – 5,7) = -3,1.(-2,7) = 8,37
F = - 3,1.(3 – 5,7) = -3,1.3 + 3,1. 5,7= -9,3 + 17,67 = 8,37
![](https://rs.olm.vn/images/avt/0.png?1311)
a, C1 : E = 5,5.( 2 - 3,6 )
= 5,5. ( -1.6 )
= -8,8
C2 : E = 5,5.( 2- 3,6 )
= 5,5.2 - 5,5.3,6
= 11 - 19,8
= -8,8
b, C1 = -3,1. ( 3 - 5,7 )
= -3,1. ( -2,7 )
= 8,37
C2 = -3,1.(3 - 5,7)
= -3,1.3 - ( -3,1. 5,7 )
= -9,3 - ( -17,67 )
= -9,3 + 17,67
= 8,37
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
E\(=5,5.\left(-1,6\right)\)=-8,8
\(E=5,5.2-5,5.3,6\)=11-19,8=-8,8
F= -3,1.(-2,7)=8,37
F=-3,1.3+3,1.5,7=-9,3+17,67=8,37
C1:E=5,5.(2-3,6)
E=5,5.(-1,6)
E=-8,8
C2:E=5,5(2-3,6)
E=5,5.2-5,5.3,6
E=11-19,8
E=-8,8
C1:F=-3,1(3-5,7)
F=-3,1.(-2,7)
F=8,37
C2:F=-3,1(3-5,7)
F=-3,1.3-(-3,1).5,7
F=-9,3-(-17,67)
F=-9,3+17,67
F=8,37
![](https://rs.olm.vn/images/avt/0.png?1311)
E=5,5.(−1,6)=-8,8
E=5,5.2−5,5.3,6=11-19,8=-8,8
F= -3,1.(-2,7)=8,37
F=-3,1.3+3,1.5,7=-9,3+17,67=8,37
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
- \(E=5,5.\left(2-3,6\right)\)
C1: \(E=5,5.\left(2-3,6\right)=-1,6.5,5=-8,8\)
C2: \(E=5,5.\left(2-3,6\right)=5,5.2-5,5.3,6=11-19,8=-8,8\)
- \(F=-3,1.\left(3-5,7\right)\)
C1: \(F=-3,1.\left(3-5,7\right)=-3,1.\left(-2,7\right)=8,37\)
C2: \(F=-3,1.\left(3-5,7\right)=-3,1.3+\left[\left(-3,1\right).\left(-5,7\right)\right]=-9,3+17,67=8,37\)
Bài 2:
a, \(\left|2,5-x\right|=1,3\Rightarrow\left[{}\begin{matrix}2,5-x=1,3\\2,5-x=-1,3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1,2\\x=3,8\end{matrix}\right.\)
\(\Rightarrow\left\{x_1=1,2;x_2=3,8\right\}\)
b, \(1,6-\left|x-0,2\right|=0\Rightarrow\left|x-0,2\right|=1,6\)
\(\Rightarrow\left[{}\begin{matrix}x-0,2=1,6\\x-0,2=-1,6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1,8\\x=-1,4\end{matrix}\right.\)
\(\Rightarrow\left\{x_1=1,8;x_2=-1,4\right\}\)
c, \(\left|x-1,5\right|+\left|2,5-x\right|=0\)
Không có giá trị của x thỏa mãn.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(E=\left(2x-5\right)^{10}-12\ge-12\)
Dấu "=" xảy ra \(\Leftrightarrow x=\dfrac{5}{2}\)
Vậy \(E_{min}=-12\Leftrightarrow x=\dfrac{5}{2}\)
\(F=\left(x+5\right)^8+\left|x+5\right|+22\ge22\)
Dấu "=" xảy ra \(\Leftrightarrow x=-5\)
Vậy \(F_{min}=22\Leftrightarrow x=-5\)
\(G=17-\left|3x-2\right|\)
Dấu "=" xảy ra \(x=\dfrac{2}{3}\)
Vậy \(G_{max}=17\Leftrightarrow x=\dfrac{2}{3}\)
\(K=17-\left|3x-2\right|-\left(2-3x\right)^{2020}\le17\)
Dấu "=" xảy ra \(\Leftrightarrow x=\dfrac{2}{3}\)
Vậy \(K_{max}=17\Leftrightarrow x=\dfrac{2}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(-3,8) + [(-5,7) + ( +3,8)] = [(-3,8) + (+3,8)] + (-5,7)
= 0 + (-5,7) = -5,7
Cách 1: E= 5,5.2-5,5.3,6=11-19,8=-8,8
cách 2: E=5,5.(-1.6)=-8,8
Cách 1: F=(-3,1).3-(-3,1).5,7=-9,3+17,67=8,37
Cách 2:(-3,1).(-2,7)=8,37
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