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a, \(2\dfrac{1}{3}+4\dfrac{1}{5}+4\dfrac{1}{3}\)
\(=\dfrac{7}{3}+\dfrac{21}{5}+\dfrac{13}{3}\)
\(=\dfrac{1}{3}\left(7+13\right)+\dfrac{21}{5}\)
\(=\dfrac{20}{3}+\dfrac{21}{5}=\dfrac{100+63}{15}=\dfrac{163}{15}\)
b, \(5\dfrac{3}{4}-4\dfrac{1}{2}.3\dfrac{7}{8}\)
\(=\dfrac{23}{4}-\dfrac{9}{2}.\dfrac{31}{8}\)
\(=\dfrac{23}{4}-\dfrac{279}{16}=\dfrac{92-279}{16}=-\dfrac{187}{16}\)
c, \(1\dfrac{1}{2}.3\dfrac{2}{3}.4\dfrac{3}{4}\)
\(=\dfrac{3}{2}.\dfrac{11}{3}.\dfrac{19}{4}=\dfrac{209}{8}\)
d, \(6\dfrac{4}{5}:2\dfrac{3}{4}:1\dfrac{1}{2}\)
\(=\dfrac{34}{5}:\dfrac{11}{4}:\dfrac{3}{2}\)
\(=\left(\dfrac{34}{5}.\dfrac{4}{11}\right).\dfrac{2}{3}=\dfrac{136}{55}.\dfrac{2}{3}=\dfrac{272}{165}\)
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\(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}\)
\(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(\frac{1}{2}-\frac{1}{6}=\frac{1}{3}\)
Tính nhanh :
1/2*3 + 1/3*4 + 1/4*5 + 1/5*6
= 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6
= 1/2 - 1/6
= 6/12 - 2/12
= 4/12
= 1/3
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\(A=\frac{1}{1+2}+\frac{1}{1+2+3}+...+\frac{1}{1+2+3+..+10}\)
\(=\frac{1}{3}+\frac{1}{6}+...+\frac{1}{55}\)
\(=2\left(\frac{1}{6}+\frac{1}{12}+...+\frac{1}{110}\right)\)
\(=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{10}-\frac{1}{11}\right)=2.\left(\frac{1}{2}-\frac{1}{11}\right)=2.\frac{9}{22}=\frac{9}{11}\)
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A=1/1*2+1/2*3+...+1/9*10
=1-1/2+1/2-1/3+...+1/9-1/10
=(1-1/10)+(1/2-1/2)+...+(1/9-1/9)
=(10/10-1/10)+0+...+0=9/10
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1. \(11\frac{2}{9}+8\frac{3}{5}+8\frac{7}{9}+1\frac{2}{5}\)
\(=\frac{101}{9}+\frac{43}{5}+\frac{79}{9}+\frac{7}{5}\)
\(=\left(\frac{101}{9}+\frac{79}{9}\right)+\left(\frac{43}{5}+\frac{7}{5}\right)\)
\(=20+10\)
\(=30\)
\(4\frac{2}{3}+5\frac{1}{2}+\frac{1}{3}+4\frac{1}{2}\)
\(=\frac{14}{3}+\frac{11}{2}+\frac{1}{3}+\frac{9}{2}\)
\(=\left(\frac{14}{3}+\frac{1}{3}\right)+\left(\frac{11}{2}+\frac{9}{2}\right)\)
\(=5+10\)
\(=15\)
Phần c bạn làm tương tự .
2. Đổi : \(2\frac{3}{4}m=\frac{11}{4}m=275m;1\frac{1}{2}m=\frac{3}{2}m=150m\)
Chiều rộng hình chữ nhật đó là :
275 - 150 = 125 ( m )
Chu vi hình chữ nhật đó là :
( 275 + 125 ) x 2 = 800 ( m )
Diện tích hình chữ nhật đó là :
275 x 125 = 34 375 ( m2 )
Đ/S : ...
bài 1:
a,11 2/9 + 8 7/9 + 1 2/5
=(11 2/9 + 8 7/9) + (8 3/5 + 1 2/5)
=20 + 10
=30.
b,4 2/3 + 5 1/2 + 1/3 + 4 1/2
=(4 2/3 + 1/3)+(5 1/2 + 4 1/2)
=5 + 10
=15.
c,19 2/7 + 5 3/4 + 4 1/4 - 9 2/7
=(19 2/7 - 9 2/7) + (5 3/4 + 4 1/4)
=10 + 10
=20.
bài 2:
2 3/4m = 275m
1 1/2m = 150m
Chiều rộng hình chữ nhật là:
275 - 150 = 125 (m)
Chu vi hình chữ nhật là:
(275+125)*2=800(m)
Diện tích hình chữ nhật là:
125 * 275 = 34375 (m)
Đáp số: 34375 m.
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\(A=\frac{3}{1}+\frac{3}{\frac{\left(2+1\right).2}{2}}+\frac{3}{\frac{\left(3+1\right).3}{2}}+....+\frac{3}{\frac{\left(100+1\right).100}{2}}\)
\(\Rightarrow A=\frac{3}{1}+\frac{6}{2.3}+\frac{6}{3.4}+...+\frac{6}{100.101}\)
\(\Rightarrow A=\frac{3}{1}+6.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-...-\frac{1}{101}\right)\)
\(\Rightarrow A=\frac{3}{1}+6.\left(\frac{1}{2}-\frac{1}{101}\right)\)
\(\Rightarrow A=\frac{3}{1}+\frac{6.99}{202}=\frac{297}{101}+\frac{3}{1}=\frac{600}{101}\)
kết quả k bik có sai k
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a) \(35\times17+84\times35-35\)
\(=35\times\left(17+84-1\right)\)
\(=35\times100=3500\)
b) \(\frac{5}{2}\times\frac{1}{3}-\frac{1}{4}=\frac{5}{6}-\frac{1}{4}=\frac{7}{12}\)
c) \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right).....\left(1-\frac{1}{2017}\right)\left(1-\frac{1}{2018}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{2016}{2017}.\frac{2017}{2018}\)
\(=\frac{1}{2018}\)
a)35x17+84x35-35
=35x(17+84-1)
=35x100
=3500
b)5/2x1/3-1/4
=5/6-1/4
=7/12
c)(1-1/2)x(1-1/3)x(1-1/4)x......x(1-1/2018)
=1/2x2/3x3/4x...x2017/2018
=1/2018
bạn cứ chép thế ko hiểu thì thôi
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\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
\(\Rightarrow A=\frac{1}{2}-\frac{1}{8}\)
\(\Rightarrow A=\frac{3}{8}\)
\(A=\left(\frac{1}{2}-\frac{1}{3}\right)+\left(\frac{1}{3}-\frac{1}{4}\right)+...+\left(\frac{1}{7}-\frac{1}{8}\right)\)
\(A=\frac{1}{2}-\frac{1}{8}\)
\(A=\frac{3}{8}\)
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3 x 15 + 21 x 15 + 85 x 5
= 45 + 315 + 425
= 785
15 - 30 + 40
= 25
21 + 19 - 50 + 10
= 0
\(\dfrac{1}{5}-\dfrac{1}{4}+2\)
\(=-\dfrac{1}{20}+2\)
\(=\dfrac{39}{20}\)
\(\left(\dfrac{1}{4}+\dfrac{1}{6}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\)
\(=\dfrac{5}{12}\times\dfrac{1}{4}\)
\(=\dfrac{5}{12}\times\dfrac{3}{12}\)
\(=\dfrac{5}{48}\)
\(\dfrac{1}{10}+\dfrac{1}{5}-\dfrac{3}{4}\)
\(=-\dfrac{9}{20}\)
\(3\times15+21\times15+85\times5\\ =15\times\left(3+21\right)+425\\ =15\times24+425\\ =360+425\\ =785\)
\(15-30+40\\ =\left(15+40\right)-30\\ =55-30\\ =25\)
\(21+19-50+10\\ =\left(21+19\right)-\left(50-10\right)\\ =40-40\\ =0\)
\(\dfrac{1}{5}-\dfrac{1}{4}+2\)
\(=\dfrac{4}{20}-\dfrac{5}{20}+\dfrac{40}{20}\)
\(=\dfrac{\left(4+40\right)}{20}-\dfrac{5}{20}\)
\(=\dfrac{44}{20}-\dfrac{5}{20}\)
\(=\dfrac{39}{20}\)
\(\left(\dfrac{1}{4}+\dfrac{1}{6}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\)
\(=\dfrac{5}{12}\times\dfrac{1}{4}\)
\(=\dfrac{5}{48}\)
\(\dfrac{1}{10}+\dfrac{1}{5}-\dfrac{3}{4}\)
\(=\dfrac{2}{20}+\dfrac{4}{20}-\dfrac{15}{20}\)
\(=\dfrac{6}{20}-\dfrac{15}{20}\)
\(=-\dfrac{9}{20}\)