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Ý bạn là mỗi phép tính phải thêm dấu và ....để kết quả bằng 6 phải không ạ
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Giải:
\(\left(10^2+8^2+6^2+4^2+2^2\right)-\left(1^2+3^2+5^2+7^2+9^2\right)\)
\(=10^2+8^2+6^2+4^2+2^2-1^2-3^2-5^2-7^2-9^2\)
\(=10^2-9^2+8^2-7^2+6^2-5^2+4^2-3^2+2^2-1^2\)
\(=\left(10^2-9^2\right)+\left(8^2-7^2\right)+\left(6^2-5^2\right)+\left(4^2-3^2\right)+\left(2^2-1^2\right)\)
\(=\left(10-9\right)\left(10+9\right)+\left(8-7\right)\left(8+7\right)+\left(6-5\right)\left(6+5\right)+\left(4-3\right)\left(4+3\right)+\left(2-1\right)\left(2+1\right)\)
\(=\left(10+9\right)+\left(8+7\right)+\left(6+5\right)+\left(4+3\right)+\left(2+1\right)\)
\(=10+9+8+7+6+5+4+3+2+1\)
\(=55\)
Vậy ...
![](https://rs.olm.vn/images/avt/0.png?1311)
= \(10^2+8^2+6^2+4^2+2^2-9^2-7^2-5^2-3^2-1\)-1
=\(55\)
\(\left(10^2+8^2+6^2+4^2+2^2\right)-\left(9^2+7^2+5^2+3^2+1^2\right)\)
\(=10^2+8^2+6^2+4^2+2^2-9^2-7^2-5^2-3^2-1^2\)
\(=\left(10^2-9^2\right)+\left(8^2-7^2\right)+...+\left(2^2-1^2\right)\)
\(=\left(10-9\right)\left(10+9\right)+\left(8-7\right)\left(8+7\right)+...+\left(2-1\right)\left(1+2\right)\)
\(=10+9+8+7+...+2+1\)
\(=\frac{\left(1+10\right)\cdot10}{2}\)
\(=55\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(10^2+8^2+6^2+4^2+2^2)-(9^2+7^2+5^2+3^2+1^2)
=102+82+62+42+22-92-72-52-32-12
=(102-92)+(82-72)+(62-52)+(42-32)+(22-12)
=(10-9)(10+9)+(8-7)(8+7)+(6-5)(6+5)+(4-3)(4+3)+(2-1)(2+1)
=10+9+8+7+6+5+4+3+2+1
=55
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(10^2+8^2+6^2+4^2+2^2\right)-\left(9^2+7^2+5^2+3^2+1^2\right)=220-165=55\)