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a) 21 - 22 + 23 - 24
= (21 - 22) + (23 - 24)
= (-1) + (-1) = -2
b) 125 - (115 - 99)
= 125 - 115 + 99
= (125 - 115) + 99
= 10 + 99 = 109.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.21-22+23-24\)
\(=\left(-1\right)+\left(-1\right)=-2\)
\(b.125-\left(115-99\right)\)
\(=125-16=109\)
![](https://rs.olm.vn/images/avt/0.png?1311)
=123+124+125-113-114-115
=(123-113)+ (124-114)+ (125-115)
=10+10+10
=30
\(\text{(123+ 124 + 125) – (113 + 114 + 115)}\)
\(=123+124+125-113-114-115\)
\(=\left(123-113\right)+\left(124-114\right)+\left(125-115\right)\)
\(=10+10+10=30.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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a) Ta có: \(\left(\dfrac{617}{191}+\dfrac{29}{33}-\dfrac{115}{17}\right)\cdot\left(\dfrac{1}{4}-\dfrac{1}{5}-\dfrac{1}{20}\right)\)
\(=\left(\dfrac{617}{191}+\dfrac{29}{33}-\dfrac{115}{17}\right)\cdot\left(\dfrac{5}{20}-\dfrac{4}{20}-\dfrac{1}{20}\right)\)
\(=0\cdot\left(\dfrac{617}{191}+\dfrac{29}{33}-\dfrac{115}{17}\right)=0\)
b) Ta có: \(\dfrac{12}{5}\cdot\left(\dfrac{10}{3}-\dfrac{5}{12}\right)\)
\(=\dfrac{12}{5}\cdot\left(\dfrac{40}{12}-\dfrac{5}{12}\right)\)
\(=\dfrac{12}{5}\cdot\dfrac{35}{12}\)
=7
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(a)\left(-17\right)+\left(-23\right)+44=-40+44=4\)
\(b)\left(-39\right)+\left(-16\right)+39=\left[\left(-39\right)+39\right]+\left(-16\right)=0+\left(-16\right)=-16\)
a) 285 + 470 + 115 + 230
= (285 + 115) + (470 + 230)
= 400 + 700
= 1 100
b) 571 +216 + 129 + 124
= (571 + 129) + (216 + 124)
= 700 + 340
= 1 040.