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45-58+(-45)+(+58)-3=45-58-45+58-3=(45-45)+(58-58)-3=-3
(-57)-(-12)+3-(-57)=-57+12+3+57=(-57+57)+12+3=15
-(-24)-(-30)+(-24)-30+8=24+30-24-30+8=(24-24)+(30-30)+8=8
-(-12)+(+19)-(+12)+8-19=12+19-12+8-19=(12-12)+(19-19)+8=8
47-(-53)+(-47)-(+53)=47+53-47-53=(47-47)+(53-53)=0
-(+28)+32-(-28)+(-34)=-28+32+28-34=(-28+28)-(34-32)=-2
15-(+72)+(-15)+(+72)=15-72-15+72=(15-15)+(72-72)=0
20-(+46)+(-25)-(-46)=20-46-25+46=(20-25)+(46-46)=-5
28-(-32)+(-28)-32+5=28+32-28-32+5=(28-28)+(32-32)+5=5
-75+(-49)+(+75)+49-12=-75-49+75+49-12=(-75+75)+(49-49)-12=-12
\(...=45-58-45+58-3=-3\)
\(...=-57+12+3+57=15\)
\(...=24+30-24-30+8=8\)
\(...=12+19-12+8-19=8\)
\(...=47+53-47-53=0\)
\(...=-28+32+28-34=-2\)
\(...=15-72-15+72=0\)
\(...=20-46-25+46=-5\)
\(=...28+32-28-32+5=5\)
\(...=-75-49+75+49-12=-12\)
Bài 2:
a. $=62-81-12+59-9=(62-12)+(59-9)-81$
$=50+50-81=100-81=19$
b. $=39+13-26-62-39=(39-39)+13-(26+62)$
$=0+13-88=-(88-13)=-75$
c. $=(32-42)+(36-34)+(40-38)=10+2+2=14$
d. $=92-55+8-45=(92+8)-(55+45)=100-100=0$
Bài 1:
a. $=(387-87)-224=300-224=76$
b. $=-(75+35)+379=-110+379=379-110=269$
c. $=(11+15)-(13+17)=25-30=-5$
d. $=(31-21)-(27-24)=10-3=7$
a) ( − 4 ) .13. ( − 250 ) = ( − 4 ) . ( − 250 ) .13 = 1000.13 = 13000
b) ( − 37 ) .84 + 37. ( − 16 ) = ( − 37 ) .84 + ( − 37 ) .16 = ( − 37 ) . ( 84 + 16 ) = ( − 37 ) .100 = − 3700
c) 25. ( − 5 ) .4. ( − 20 ) = 25.4. ( − 5 ) . ( − 20 ) = 100.100 = 10000
d) ( − 48 ) .72 + 36. ( − 304 ) = ( − 48 ) .2.36 + 36. ( − 304 ) = ( − 96 ) .3 + 36. ( − 304 )
2) 
3) 
4) 
1.a) 4.(12+88) = 4.100=400
b)72- 6 .[2.8:8 ]=72-6.[16:8]=72-6 .2= 49-12=37 ( tui ko chắc lắm )
2.a) x=26-11=15
b) (4x-15)3=53
4x-15=5
4x= 5+15
4x=20
vậy x = 20
Bài 2:
a: Ta có: x+11=26
nên x=15
b: Ta có: \(\left(4x-15\right)^3=125\)
\(\Leftrightarrow4x-15=5\)
hay x=5
a) 52 – 42 + 37 – 28 + 38 + 63 = (52 – 42) + (37 + 63) + (38 – 28) = 10 + 100 + 10 = 120
b) 130 + 35.19 – 9.70 – 30
= (35.19 – 9.70) + (130 – 30) = (35.19 – 9.35.2) + 100 = 35.(19 – 18) + 100 = 35 + 100 = 135
c) (11 + 13 + 15 + … + 19).(6.8 – 48) = (11+13+15+…+19).0 = 0
d) (72 – 8.9):(20+22+24 – 19 +21+23) = 0:(20+22+24 – 19 +21+23) = 0
Bài 1:
a. A = 125 . (-61) . (-2)3 . (-1)24
= 125. (-8). (-61) . 124
= 125. 8. 61.1
= 1000. 61 = 61000
b. B = 136. (-47) + 36.47
= (-136).47 + 36.47
= 47. (-136 + 36)
= 47. (-100) = -4700
c. C = (-48).72 + 36.(-304)
= (-96).36 + 36. (-304)
= 36. (-96-304)
= 36. (-400) = -14400
d. D = 87.(13-18) - 13.(87 + 18)
= 87.13 - 87.18 - 13.87 - 13.18
= - 87.18 - 18.13
= - 18.(87+13)
= - 18.100 = -1800
Bài 2:
a. TH1: x - 2 = 0 => x = 2
TH2: 5-x = 0 => x = 5
b. |x| = 56 - 23 = 33 => x = cộng trừ 33
c. 3 - (17-x) = 289 - (36 + 289)
=> 3 - 17 + x = 289 - 289 - 36
=> -14 + x = -36
=> x = -36 - (-14) = -22
1.
a. A = 125 . (-61) . (-2)3 . (-1)24
= 125.(-61).(-8).1
= (-8.125).(-61)
= -1000.(-61)
= 61000
b. B = 136 . (-47) + 36 . 47
=-136.47+36.47
=47(-136+36)
= 47.(-100)
= -4700
2.
a. (x - 2) . (5 - x) = 0
=> x - 2 = 0 hoặc 5 - x = 0
=> x = 2 hoặc x = 5
b. 56 - lxl = 23
=> |x| = 33
=> x = 33 hoặc x = -33
c. 3 - (17 - x) = 289 - (36 + 289)
=> 3 - 17 + x = 289 - 36 - 289
=> -14 + x = -36
=> x = -22
a: \(24\cdot35+65\cdot24-1400\)
\(=24\left(35+65\right)-1400\)
\(=24\cdot100-1400=2400-1400=1000\)
b: \(32:2^4-4\cdot5^2\)
\(=\dfrac{32}{16}-4\cdot25\)
=2-100
=-98
c: \(17+75:\left[30-5\cdot\left(7^2-48\right)\right]\)
\(=17+75:\left[30-5\cdot\left(49-48\right)\right]\)
\(=17+75:\left[30-5\right]\)
\(=17+\dfrac{75}{25}=17+3=20\)
d: \(\left(-138\right)-\left[258+4\cdot\left(-36\right)\right]\cdot2024^0\)
\(=-138-\left[258-144\right]\)
\(=-138-114\)
=-252