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\( (-11).77 - 23.11 + (-29) \)
\(=11.(-77)-23.11+(-29)\)
\(=11.[(-77)-23]+(-29)\)
\(=11.(-100)+(-29)\)
= -1100 + (-29)
= -(1100+29)=-1071
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=6+\dfrac{4}{9}+\dfrac{7}{11}-4-\dfrac{4}{9}+2+\dfrac{4}{11}=4+1=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1500-\left\{5^3\cdot2^3-11\left[7^2-5\cdot2^3+8\left(11^2-121\right)\right]\right\}\\ =1500-\left[125\cdot8-11\left(49-5\cdot8+8\cdot0\right)\right]\\ =1500-\left[125\cdot8-11\left(49-40+0\right)\right]\\ =1500-\left(125\cdot8-11\cdot9\right)\\ =1500-\left(1000-99\right)\\ =1500-901\\ =599\)
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\(A=\left(25^6+15^6-10^6\right)\div5^6\)
\(A=\left(25+15-10\right)^6\div\left(5^6\right)\)
\(A=30^6\div5^6\)
\(A=\left(30\div5\right)^6\)
\(A=6^6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{1\cdot2+2\cdot4+3\cdot6+4\cdot8+5\cdot10+6\cdot12}{3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20+18\cdot24}\)
\(A=\frac{2\cdot3\left[1\cdot2\right]+2\cdot3\left[2\cdot4\right]+2\cdot3\left[3\cdot6\right]+2\cdot3\left[4\cdot8\right]+2\cdot3\left[5\cdot10\right]}{3\cdot4\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}\)
\(A=\frac{\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}{2\cdot3\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}=\frac{1}{2\cdot3}=\frac{1}{6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(100a+10b+6\)
\(=2\left(50a+5b+3\right)\)
\(100a+50+c\)
\(=50\left(2a+1\right)+c\)
\(\left(-6\right).3+6.\left(-11\right)+\left(-6\right).\left(-2\right)\)
\(=\left(-6\right).3+\left(-6\right).11+\left(-6\right).\left(-2\right)\)
\(=\left(-6\right).\left[3+11+\left(-2\right)\right]\)
\(=\left(-6\right).12\)
\(=-72\)