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![](https://rs.olm.vn/images/avt/0.png?1311)
a , 56 , 41 + 169 , 7 ⏟ : 12 = 225 , 48 : 12 = 18 , 79 b , 6993 : 315 × 2 , 5 + 61 , 7 = 22 , 2 × 2 , 5 ⏟ + 61 , 7 = 55 , 2 + 61 , 7 = 117 , 2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Với a = 3,05 thì ta có:
\(a\times2,46\) \(=3,05\times2,46=7,503\)
b) Với \(a=\dfrac{15}{8}\) thì ta có:
\(\left(\dfrac{5}{6}+\dfrac{7}{12}\right):a\) \(=\left(\dfrac{5}{6}+\dfrac{7}{12}\right):\dfrac{15}{8}\) \(=\left(\dfrac{10}{12}+\dfrac{7}{12}\right)\times\dfrac{8}{15}\) \(=\dfrac{17}{12}\times\dfrac{8}{15}\) \(=\dfrac{34}{45}\)
a) Thay a=3,05 vào 2,46a, ta được:
\(2.46\cdot3.05=7.503\)
b) Thay \(a=\dfrac{15}{8}\) vào biểu thức \(\left(\dfrac{5}{6}+\dfrac{7}{12}\right):a\), ta được:
\(\left(\dfrac{5}{6}+\dfrac{7}{12}\right):\dfrac{15}{8}\)
\(=\dfrac{17}{12}\cdot\dfrac{8}{15}=\dfrac{34}{45}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a. 15,36 x 4 + 1,98 x 5
= 61,44 + 9,9
= 71,34
( 15,36 + 1,98) x7
= 17,34 x 7
= 121,38
b. 15,36 x 4 - 1,98 x 5
= 61,44 - 9.9
= 51,54
( 15,36 - 1,98) x 7
= 13,38 x 7
= 93,66
![](https://rs.olm.vn/images/avt/0.png?1311)
Phần a là 0
Phần b là 5
Phần c là 6
Phần d là 1
Phần e là 0
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{1}{4}+\frac{1}{12}+\frac{1}{36}+\frac{1}{108}+\frac{1}{324}\)
\(3A=3\left(\frac{1}{4}+\frac{1}{12}+\frac{1}{36}+\frac{1}{108}+\frac{1}{324}+\frac{1}{972}\right)\)
\(3A=\frac{3}{4}+\frac{3}{12}+\frac{3}{36}+\frac{3}{108}+\frac{3}{324}+\frac{3}{927}\)
\(3A=\frac{3}{4}+\frac{1}{4}+\frac{1}{12}+\frac{1}{36}+\frac{1}{108}+\frac{1}{324}\)
\(2A=3A-A\)
\(2A=\left(\frac{3}{4}+\frac{1}{4}+\frac{1}{12}+\frac{1}{12}+\frac{1}{36}+\frac{1}{108}+\frac{1}{324}\right)-\left(\frac{1}{4}+\frac{1}{12}+\frac{1}{36}+\frac{1}{108}+\frac{1}{324}+\frac{1}{972}\right)\)
\(2A=\frac{3}{4}-\frac{1}{927}\)
\(2A=\frac{729-1}{972}=\frac{728}{972}=\frac{182}{243}\)
\(A=\frac{182}{243}:\frac{1}{2}\)
\(A=\frac{364}{243}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(2\dfrac{3}{5}+1\dfrac{2}{5}\cdot\dfrac{31}{2}\)
\(=\dfrac{13}{5}+\dfrac{7}{5}\cdot\dfrac{31}{2}\)
\(=\dfrac{26}{10}+\dfrac{217}{10}=\dfrac{243}{10}\)
b: \(4\dfrac{3}{4}-3\dfrac{2}{3}:1\dfrac{1}{6}\)
\(=\dfrac{19}{4}-\dfrac{11}{3}:\dfrac{7}{6}\)
\(=\dfrac{19}{4}-\dfrac{11}{3}\cdot\dfrac{6}{7}\)
\(=\dfrac{19}{4}-\dfrac{22}{7}\)
\(=\dfrac{19\cdot7-22\cdot4}{28}=\dfrac{45}{28}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
- Tính giá trị biểu thức:
a) (2/5 x 25/29) + (3/5 x 25/29)
= (50/145) + (75/145)
= 125/145
b) (5/2 x 3/7) - (3/14 : 6/7)
= 15/14 - (3/14 x 7/6)
= 15/14 - 1/2
= (30/28) - (14/28)
= 16/28
= 4/7
c) (15/4 : 5/12) - (6/5 : 11/15)
= (15/4 x 12/5) - (6/5 x 15/11)
= 180/20 - 90/55
= 9 - 18/11
= (99/11) - (18/11)
= 81/11
= 7 4/11
- Tính giá trị biểu thức:
a) (2/3) + (20/21 x 3/2 x 7/5)
= 2/3 + (60/210)
= 2/3 + 2/7
= (14/21) + (6/21)
= 20/21
b) (5/17 x 21/32 x 47/24 x 0)
= 0
c) (11/3 x 26/7) - (26/7 x 8/3)
= (286/21) - (208/21)
= 78/21
= 3 9/21
= 3 3/7
- Tìm x:
a) (25/8) : x = 5/16
=> (25/8) x (16/5) = x
=> 4 = x
b) x + (7/15) = 6/15
=> x = (6/15) - (7/15)
=> x = -1/15
c) x : (28/49) = 7/12
=> x x (49/28) = 7/12
=> x = (7/12) x (28/49)
=> x = 1/2
- Tìm x:
a) 6 x x = (5/8) : (3/4)
=> 6x = (5/8) x (4/3)
=> 6x = 20/24
=> 6x = 5/6
=> x = (5/6) / 6
=> x = 5/36
câu,b,không,đủ,thông,tin,nhan,bạn.
a)
56 , 41 + 169 , 7 ⏟ : 12 = 225 , 48 : 12 = 18 , 79
b)
6993 : 315 × 2 , 5 + 61 , 7 = 22 , 2 × 2 , 5 ⏟ + 61 , 7 = 55 , 2 + 61 , 7 = 117 , 2