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a, 2 x 9 x 5 x 7 x 4 x 25
= 23 x 32 x 53 x 7
= 63000
b, 6 x 14 x 5 x 25 x 3 x 4
= 24 x 32 x 53 x 7
= 126000
a) 2x9x5x7x4x25
= (2x5)x(4x25)x(9x7)
= 10x100x63
= 63000
b) 2x14x5x25x3x4
= (2x5)x(4x25)x(14x3)
= 10x100x42
= 42000
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a) \(\dfrac{3}{5}\times\dfrac{17}{21}+\dfrac{17}{21}\times\dfrac{2}{5}\)
\(=\dfrac{17}{21}\times\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\)
\(=\dfrac{17}{21}\times1\)
\(=\dfrac{17}{21}\)
b) \(\dfrac{15}{8}:\dfrac{5}{20}-\dfrac{7}{8}:\dfrac{1}{4}\)
\(=\dfrac{15}{8}\times\dfrac{20}{5}-\dfrac{7}{8}\times4\)
\(=\dfrac{15}{8}\times4-\dfrac{7}{8}\times4\)
\(=4\times\left(\dfrac{15}{8}-\dfrac{7}{8}\right)\)
\(=4\times1\)
\(=4\)
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a) 35 x 2 x 9 x 5
= (35 x 9) x (2 x 5)
= (35 x 10 - 35) x 10
= (350 - 35) x 10
= 315 x 10 = 3150
b) 24 x 71 + 71 x 75 + 71
= 71 x (24+75+1)
=71 x 100
= 7100
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(995 x 37 + 1000) : (39 x 995 - 990)
= (36815 + 1000) : (38805 - 990)
= 37815 : 37815
= 1
(995 x 37 + 1000 ) : ( 39 x 995 - 990)
= ( 36815 + 1000) : ( 38805 - 990 )
= 37815 : 37815
=1
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a: Ta có: 24+35+76+65+22
=(24+76)+(35+65)+22
=222
b: Sửa đề: \(24\cdot35+24\cdot65\)
=24x100
=2400
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a) (48 x 55) : 8
= (48:8)x55
= 6x55
= 330
b) (164 x 42) : 7
= 164x(42:7)
= 164x6
= 984
c) (135 x 25) : 5
= 135x(25:5)
= 135x5
= 675
d) (147 x 12) : 6
= 147x(12:6)
= 147x2
= 294
(Nếu đúng thì cho mk tick nhé)
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a) 142 x 12 + 142 x 18
= 142 x ( 18 + 12 )
= 142 x 30
= 4260
b) 49 . 365 - 39 . 365
= 365 . ( 49 - 39)
= 365 . 10
= 3650
c) 4 . 18 . 25
= 18 . 4 . 25
= 18 . 100
= 1800
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Bài 2: Tính bằng cách thuận tiện nhất
\(\text{a. 1255 + 436 + 145}\)
\(=\left(1255+145\right)+436\)
\(=1400+436\)
\(=1836\)
\(\text{b. 142 x 12 + 142 x 18}\)
\(=142\times\left(12+18\right)\)
\(=142\times30\)
\(=4260\)
\(\text{c. 4 x 18 x 25}\)
\(=\left(25\times4\right)\times18\)
\(=100\times18\)
\(=1800\)
Bài 2:
a: \(=1400+436=1836\)
b: =142(12+18)
=142*30
=4260
c: \(=100\cdot18=1800\)
Bài 3:
a: \(41m^219dm^2>409dm^2\)
b: \(90000cm^2< 90m^2\)
c: \(30m^26dm^2< 3060dm^2\)
d: \(8012cm^2>8dm^212cm^2\)
e: \(5dm^29cm^2=509cm^2\)
f: \(3940dm^2=39m^240dm^2\)
g: \(300m^26dm^2>3006dm^2\)
h: \(2009cm^2< 21dm^2\)
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