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A=\(\frac{2}{1}\cdot3+\frac{2}{3}\cdot5+\frac{2}{5}\cdot7+\frac{2}{7}\cdot9\)
A=\(\frac{3}{1}\cdot2+\frac{5}{3}\cdot2+\frac{7}{5}\cdot2+\frac{9}{7}\cdot2\)
A=\(2\cdot\left(3+\frac{5}{3}+\frac{7}{5}+\frac{9}{7}\right)\)
A=\(2\cdot\frac{772}{105}\)
A=\(\frac{1544}{105}\)
A=\(14\frac{74}{105}\)
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9,3 x 6,7 + 9,3 x 3,3 = 9,3 x ( 6,7 + 3,3 )
= 9,3 x 10
= 93
7,8 x 0,35 + 0,35 x 2,2 = 0,35 x ( 7,8 + 2,2 )
= 0,35 x 10
= 3,5
Đáp án là:
a) 9,3 x 6,7 + 9,3 x 3,3
= 9,3 x (6,7+3,3)
= 9,3 x 10
= 93.
b) 7,8 x 0,35 + 0,35 x 2,2
= 0,35 x (7,8+2,2)
= 0,35 x 10
= 35
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\(\dfrac{5}{13}\times\dfrac{7}{11}+\dfrac{5}{13}\times\dfrac{2}{11}+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{5}{13}\times\left(\dfrac{7}{11}+\dfrac{2}{11}\right)+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{5}{13}\times\dfrac{9}{11}+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{9}{11}\times\left(\dfrac{5}{13}+\dfrac{8}{13}\right)\)
\(=\dfrac{9}{11}\times1\)
\(=\dfrac{9}{11}\)
a) \(20,23\times21+20,23\times80-20,23\)
\(=20,23\times\left(21+80-1\right)\)
\(=20,23\times100\)
\(=2023\)
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Câu 1: Tìm x:
a) 2/5× x =(thiếu đề)
8/7: x =4/5
x=8/7:4/5
x=10/7
Câu 2: Tính bằng cách thuận tiện nhất
5/9× 8/17 + 4/9 × 8/17
=(5/9+4/9)x8/17
=1x8/17=8/17
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a ) \(=\frac{35\cdot42}{5\cdot2}=\frac{7\cdot5\cdot2\cdot21}{5\cdot2}\)
\(=\frac{7\cdot21}{1}=147\)
b) \(=\frac{54\cdot35}{7\cdot9}\)
\(=\frac{6\cdot9\cdot7\cdot5}{7\cdot9}\)
\(=\frac{6\cdot5}{1}=30\)
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\(\frac{2}{9}\cdot\frac{5}{7}+\frac{2}{7}\cdot\frac{2}{9}\)
\(=\frac{2}{9}\cdot\left(\frac{5}{7}+\frac{2}{7}\right)\)
\(=\frac{2}{9}\)