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Có: \(P=\left\{1;4;9;16;25;36;49;64;81\right\}\)
Ta thấy: \(1=1^2\)
\(4=2^2\)
\(9=3^2\)
\(.......\)
\(81=9^2\)
\(\Rightarrow P=\left\{x|x\in N=k^2\left(k\in\left\{1;2;3;...;9\right\}\right)\right\}\)
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a) \(-\dfrac{9}{18}+\dfrac{-18}{27}=\dfrac{-1}{2}+\dfrac{-2}{3}=\dfrac{-3}{6}+\dfrac{-4}{6}=\dfrac{-7}{6}\)
b) \(\dfrac{12}{16}-\dfrac{10}{25}=\dfrac{3}{4}-\dfrac{2}{5}=\dfrac{15}{20}-\dfrac{8}{20}=\dfrac{7}{20}\)
c) \(-2+\dfrac{-2}{3}=\dfrac{-6}{3}+\dfrac{-2}{3}=\dfrac{-8}{3}\)
d) \(\dfrac{2}{5}-1=\dfrac{2}{5}-\dfrac{5}{5}=\dfrac{-3}{5}\)
\(#NqHahh\)
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2.31.12+4.6.42+8.27.3=24.31+24.42+24.27=24.(31+42+27)=24.100=2400
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116-(115-99)
= 116 - 115 + 99
= 1 + 99
= 100
HT và $$$
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\(\left(324.359+24\right):\left(137.10+357.322\right)\)
\(=\left(116316+24\right):\left(1370+114954\right)\)
\(=116340:116324\)
\(=\dfrac{29085}{29081}\)
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1. A= { 0; 1; 2; 3; 4; 5; 6; 7; 8; 9 }
2. A= { x thuộc( kí hiệu )N l x<10 }
3. Tập hợp A có 10 phần tử.
= 39-6 - 27:26+64
=33 - 2 + 64
=9-2+64=7+64=71
\(3^9:3^6-2^7:64-2^7=3^3-2+2^7=153\)