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`@` `\text {Ans}`
`\downarrow`
\(-(-299)+(-219)+(-401)+12\)
`= 299 - 219 - 401 + 12`
`= 80 - 401 + 12`
`= -321 + 12`
`= -309`
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=-\left(-299\right)+\left(-219\right)+\left(-401\right)\)
\(\Leftrightarrow B=299-219-401\)
\(\Leftrightarrow B=-321\)
Vậy B = - 321
![](https://rs.olm.vn/images/avt/0.png?1311)
Giải:
\(A=\left[\left(-8\right)+\left(-7\right)\right]+\left(-10\right)=\left(-15\right)+\left(-10\right)=\left(-25\right)\)
\(B=-\left(-299\right)+\left(-219\right)+\left(-401\right)+12=299-219-401+12=-309\)
\(C=555+\left(-100\right)+\left(-80\right)+\left|-333\right|=555-100-80+333=708\)
\(D=\left|-347\right|+\left(-40\right)+3150+\left(-307\right)=347-40+3150-307=2456\)
\(E=98.42-\left\{50.\left[\left(18-2^3\right):2+3^2\right]\right\}\)
\(E=4116-\left\{50.\left[\left(18-8\right):2+9\right]\right\}\)
\(E=4116-\left\{50.\left[10:2+9\right]\right\}\)
\(E=4116-\left\{50.\left[5+9\right]\right\}\)
\(E=4116-\left\{50.14\right\}\)
\(E=4116-700\)
\(E=3416\)
\(F=-80-\left[-130-\left(12-4^2\right)\right]+2008^0\)
\(F=-80-\left[-130-\left(12-16\right)\right]+1\)
\(F=-80-\left[-130-\left(-4\right)\right]+1\)
\(F=-80-\left(-126\right)+1\)
\(F=47\)
\(G=1000+\left(-670\right)+297+\left(-330\right)=1000-670+297-330=297\)
\(H=1024:2^4+140:\left(38+2^5\right)-7^{23}:7^{21}\)
\(H=2^{10}:2^4+140:\left(38+32\right)-7^2\)
\(H=2^6+140:70-49\)
\(H=64+2-49\)
\(H=17\)
\(I=\left|-129\right|-119+\left|2-31\right|=129-119+\left|-29\right|=10+29=39\)
\(K=219+573+381-173\)
\(K=\left(219+381\right)+\left(573-173\right)\)
\(K=600+400\)
\(K=1000\)
\(L=36.33-105.11+22.15\)
\(L=36.33-35.3.11+11.2.3.5\)
\(L=36.33-35.33+33.10\)
\(L=33.\left(36-35+10\right)\)
\(L=33.11\)
\(L=363\)
\(N=160-\left(2^3.5^2-6.25\right)\)
\(N=160-\left[25.\left(8-6\right)\right]\)
\(N=160-\left[25.2\right]\)
\(N=160-50\)
\(N=110\)
\(O=\left(44.52.60\right):\left(11.13.15\right)=137280:2145=64\)
\(P=\left(2^{17}+15^4\right).\left(3^9-2^{17}\right).\left(2^4-4^2\right)=\left(2^{17}+15^4\right).\left(3^9-2^{17}\right).0=0\)
\(Q=100+98+96+...+4+2-97-95-...-3-1\)
\(Q=100+\left(98-97\right)+\left(96-95\right)+...+\left(4-3\right)+\left(2-1\right)\)
\(Q=100+1+1+...+1+1\)
Vì có 98:2=49 số 1
\(\Rightarrow Q=100+49\)
\(Q=149\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
- (-229) + (-219) – 401 + 12 = (229 – 219) –( 401 – 12) = 10 – 389 = -379
![](https://rs.olm.vn/images/avt/0.png?1311)
-(-229 ) + (-219 ) - 401 + 12
= 209 - 219 - 401 + 12
= -10 - 401 + 12
= -411 + 12
= - 399
300 - (-200) - (-120) + 18
= 300 + 200 + 120 + 18
= 500 + 120 + 18
= 620 + 18
= 638
- -(-229 ) + (-219 ) - 401 + 12
= 10 - 401 + 12
= -391 + 12
= -379
- 300 - (-200) - (-120) + 18
= 500 + 120 + 18
= 620 + 18
= 638
=>B=299 -219 -401+12
=>B=80-401+12
=>B=(80+12)-401
=>B=92-401
=>B=-309
B = 299 - 219 - 401 + 12
= 80 - 401 + 12
= -321 + 12
= -309