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a) \(\dfrac{6}{13}:\left(\dfrac{1}{2}-x\right)=\dfrac{15}{39}\)
\(\dfrac{1}{2}-x=\dfrac{6}{13}:\dfrac{15}{39}\)
\(\dfrac{1}{2}-x=\dfrac{6}{5}\)
\(x=\dfrac{1}{2}-\dfrac{6}{5}\)
\(x=-\dfrac{7}{10}\)
b) \(3\times\left(\dfrac{x}{4}+\dfrac{x}{28}+\dfrac{x}{70}+\dfrac{x}{130}\right)=\dfrac{60}{13}\)
\(3\times x\times\left(\dfrac{1}{4}+\dfrac{1}{28}+\dfrac{1}{70}+\dfrac{1}{130}\right)=\dfrac{60}{13}\)
\(x\times\left(\dfrac{3}{1\times4}+\dfrac{3}{4\times7}+\dfrac{3}{7\times10}+\dfrac{3}{7\times13}\right)=\dfrac{60}{13}\)
\(x\times\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}\right)=\dfrac{60}{13}\)
\(x\times\left(1-\dfrac{1}{13}\right)=\dfrac{60}{13}\)
\(x\times\dfrac{12}{13}=\dfrac{60}{13}\)
\(x=\dfrac{60}{13}:\dfrac{12}{13}\)
\(x=5\)
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`#3107`
`7/13 \div x = 14/39`
`=> x = 7/13 \div 14/39`
`=> x = 3/2`
Vậy, `x = 3/2`
________
`x \times 3/5 = 14/15`
`=> x = 14/15 \div 3/5`
`=> x = 14/9`
Vậy, `x=14/9.`
\(\dfrac{7}{13}:x=\dfrac{14}{39}\)
\(x=\dfrac{7}{13}:\dfrac{14}{39}\)
\(x=\dfrac{7}{13}\times\dfrac{39}{14}\)
\(x=\dfrac{3}{2}\)
___
\(x\times\dfrac{3}{5}=\dfrac{14}{15}\)
\(x=\dfrac{14}{15}:\dfrac{3}{5}\)
\(x=\dfrac{14}{15}\times\dfrac{5}{3}\)
\(x=\dfrac{14}{9}\)
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\(\frac{21}{36}\)x \(\frac{39}{14}\)x \(\frac{54}{13}\)= \(\frac{189}{82}\).
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Mình sửa lại đề nè:
\(x+\frac{5}{13}+\frac{10}{26}+\frac{15}{39}+\frac{20}{52}+\frac{40}{104}=\frac{25}{13}\)
\(=x+\frac{5}{13}+\frac{5}{13}+\frac{5}{13}+\frac{5}{13}+\frac{5}{13}=\frac{25}{13}\)
\(=x+\frac{5}{13}x5=\frac{25}{13}\)
\(x+\frac{25}{13}=\frac{25}{13}\)
\(x=\frac{25}{13}-\frac{25}{13}\)
\(x=0\)
Chúc bạn học tốt!
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(x - 21 x 13) : 11 + 39 = 50
(x - 273) : 11 = 50 - 39
(x - 273) : 11 = 11
x - 273 = 11 x 11
x - 273 = 121
x = 121 + 273
x = 394
vậy x = 394
[ x - 21 x 13 ] : 11 + 39 = 50
[ x - 273 ] : 11 = 50 - 39
[x - 273 ] : 11 = 11
x - 273 = 11 x 11
x - 273 = 121
x = 121 + 273
x = 394
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13/10 = 1,3; 70% = 0,7; 41/10= 4,1
1,3 + 0,7 + 4,1 + 0,59 = 6,69
\(\dfrac{70}{39}\times\dfrac{13}{14}-\dfrac{13}{25}:\dfrac{39}{50}=\dfrac{5}{3}-\dfrac{13}{25}\times\dfrac{50}{39}=\dfrac{5}{3}-\dfrac{2}{3}=1\)
\(\dfrac{70}{39}\cdot\dfrac{13}{14}-\dfrac{13}{25}:\dfrac{39}{50}\)
\(=\dfrac{5}{3}-\dfrac{13}{25}\cdot\dfrac{50}{39}\)
\(=\dfrac{5}{3}-\dfrac{2}{3}\)
=1