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Ta có: 1 + 6 + 8 = 15; 2 + 4 + 9 = 15
Vậy 1 + 6 + 8 = 2 + 4 + 9
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: 1 + 5 + 6 = 12 ; 2 + 3 + 7 = 12
Vậy 1 + 5 + 6 = 2 + 3 + 7
b) Ta có:\(1^2\)\(+5^2\)\(+6^2\)\(=1+25+36=62\)
\(2^2\)\(+4^2\)\(+7^2\)\(=4+16+49=62\)
\(=>1^2\)\(+5^2\)\(+6^2\)\(=2^2\)\(+3^2\)\(+7^2\)
c) Ta có 1 + 6 +8 = 15; 2 + 4 + 9 = 15
Vậy 1 + 6 + 8 = 2 + 4 + 9
\(d,1^2\)\(+6^2\)\(+8^2\)\(=1+36+64=101\)
\(2^2\)\(+4^2\)\(+9^2\)\(=4+16+81=101\)
\(1^2\)\(+6^2\)\(+8^2\)\(=2^2\)\(+4^2\)\(+9^2\)
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\(C1:2\dfrac{4}{9}+1\dfrac{1}{6}=\dfrac{22}{9}+\dfrac{7}{6}=\dfrac{44}{18}+\dfrac{21}{18}=\dfrac{65}{18}\)
\(C2:2\dfrac{4}{9}+1\dfrac{1}{6}=\left(2+1\right)+\left(\dfrac{4}{9}+\dfrac{1}{6}\right)=3+\dfrac{11}{18}=\dfrac{54}{18}+\dfrac{11}{18}=\dfrac{65}{18}\)
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ta có : `(-2)/9=2/(-9)`
`2/(-9) =(2 xx 3)/(-9xx3)=6/(-27)`
`->` 2 cặp p/s bằng nhau
`----`
ta có : `(-1)/(-5)=1/5`
`1/5=(1xx5)/(5xx5)=5/25`
`->` 2 cặp p/s không bằng nhau
![](https://rs.olm.vn/images/avt/0.png?1311)
1: =5/8*17/13*7/17*8/3*6
=5/3*7/13*6
=5*7*2/13=70/13
2: =-7/9(24/19-1)
=-7/9*5/19
=-35/171
3: =-3/8(7/6-9/6)
=-3/8*(-2/6)
=3/8*1/3=1/8
Bằng 9 nha bạn
= 9 nha cậu
Học Tốt !
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