Question

[Nguyễn Phan Thảo Nguyên]

Tính 3+ 1/5+128%+5,56-1-1,67+72%

Answer 1

[Nguyễn Thị Ngọc Ánh]

\(3+\frac{1}{5}+128\%+5,56-1-1,67+72\%.\)

\(=\left(3+\frac{1}{5}+5,56-1-1,67\right)+\left(128\%+72\%\right)\)

\(=6,09+200\%=6,09+2=8,09\)

học tốt ~~~

Answer 2

[Thiên Hương Nguyễn]

Ta có : \(3+\frac{1}{5}+128\%+5,56-1-1,67+72\%\)
= 3 + \(\frac{1}{5}\)+ \(\frac{128}{100}\)+ \(\frac{556}{100}\)- 1 - \(\frac{167}{100}\)+ \(\frac{72}{100}\)

= \(\frac{300}{100}\)+  \(\frac{20}{100}\)+ \(\frac{128}{100}\)+ \(\frac{556}{100}\)- \(\frac{100}{100}\)-\(\frac{167}{100}\)+\(\frac{72}{100}\)
= \(\frac{809}{100}\)
= 8,09