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x .4 - x : 4 - 24,76 = 190,48 : 2
x . 4 - x . 1/4 - 24,76 = 95,24
x .4 -x . 1/4 = 95,24 + 24,76
x .4 - x . 1/4 = 120
x . [ 4-1/4]=120
x . 15/4 = 120
x = 120 : 15/4
x = 32
X.4-x:4-24,76=190,48:2
X.4-x.1/4-24,76=95,24
X.4-x.1/4=95,24+24,76
X.4-x.1/4=120
X.(4-1/4)=120
X.15/4=120
X=120:15/14
X=32
1/2-2y=9/20
=>2y=1/2-9/20=1/20
=>y=1/20:2=1/40
b,3/5:4/3:y=2+7/10=9/20:y=27/10
=>y=9/20:27/10=1/6
c,y+y*3/2-y*1/2=1/10
=>y(1+3/2-1/2)=1/10
=>2y=1/10
=>y=1/10:2=1/20
\(\frac{\frac{1}{2\times4}+\frac{1}{4\times6}+\frac{1}{6\times8}+...+\frac{1}{98\times100}}{y}=\frac{147}{50}\)
\(\frac{\frac{1}{2}\times\left(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+...+\frac{2}{98\times100}\right)}{y}=\frac{147}{50}\)
\(\frac{\frac{1}{2}\times\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{98}-\frac{1}{100}\right)}{y}=\frac{147}{50}\)
\(\frac{\frac{1}{2}\times\left(\frac{1}{2}-\frac{1}{100}\right)}{y}=\frac{147}{50}\)
\(\frac{\frac{1}{2}\times\frac{49}{100}}{y}=\frac{147}{50}\)
\(\frac{49}{200}:y=\frac{147}{50}\)
\(y=\frac{49}{200}:\frac{147}{50}\)
\(y=\frac{1}{12}\)
Ta có : \(\frac{x}{4}=\frac{y}{7}\)
\(\Rightarrow\frac{x^2}{16}=\frac{y^2}{49}=\frac{3x^2}{48}=\frac{4y^2}{196}=\frac{3x^2-4y^2}{48-196}=\frac{100}{-148}=-\frac{25}{37}\)
Thay vào là ra nhé !:D
Cái chỗ Nguyễn Quang Trung đúng ròi
\(\Rightarrow\hept{\begin{cases}\frac{x}{4}=-\frac{25}{37}\\\frac{y}{7}=-\frac{25}{37}\end{cases}}\Rightarrow\hept{\begin{cases}x=-\frac{100}{37}\\y=-\frac{175}{37}\end{cases}}\)
a) Y x 4 - Y : 4 - 24,76 = 190,48 : 2
Y x 4 - Y x 1/4 - 24,76 = 95,24
Y x (4 - 1/4) = 95,24 + 24,76
Y x 15/4 = 120
Y = 120 : 15/4 = 32
x+x/3*15=324/4+106/6