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\(x+\frac{3}{4}=\frac{1}{2}.\frac{2}{3}\)
\(x+\frac{3}{4}=\frac{2}{6}\)
\(x=\frac{2}{6}-\frac{3}{4}\)
\(x=\frac{-5}{12}\)
x+3/4=1/2.2/3
x+3/4=1/3
x=1/3-3/4
x=-5/12
k mik nhoa!!!!!!!!!!!!!!!!!
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\(2\frac{1}{2}-x=1\frac{2}{3}\)
\(x=2\frac{1}{2}-1\frac{2}{3}\)
\(x=\frac{5}{6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
=> x + 1/2 = 5/6 + 3/4
=> x + 1/2 = 19/12
=> x = 19/12 - 1/2
=> x = 13/12
Vậy x = 13/12
Tk mk nha
a X+1/2-3/4=5/6 suy ra : Mỉnh phải đi ngủ rồi mai mình giải tiếp cho nhé
X+1/2=5/6+3/4
X+1/2=19/12
X=19/12-1/2
X=13/12
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\(\frac{3}{2}-x=\frac{1}{2}\)
\(x=\frac{3}{2}-\frac{1}{2}\)
\(x=\frac{2}{2}\)
\(x=1\)
Vậy \(x=1\)
3/2 - x = 1/2
x = 3/2 - 1/2
x = 2/2 hoặc 1
k đúng cho bạn nhé
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\(1\frac{1}{2}-x=\frac{3}{4}\)
\(x=1\frac{1}{2}-\frac{3}{4}\)
\(x=\frac{3}{4}\)
Ai nhanh mik tích cho
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\(x.\frac{2}{3}=\frac{1}{2}\)
\(x=\frac{1}{2}:\frac{2}{4}\)
\(x=1\)
x.\(\frac{2}{3}\)= \(\frac{1}{2}\)
x= \(\frac{1}{2}\): \(\frac{2}{3}\)
x= \(\frac{3}{4}\)
tk nhé
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\(x+\frac{2}{3}=3\frac{1}{3}\)
\(x=3\frac{1}{3}-\frac{2}{3}\)
\(x=\frac{8}{3}=2\frac{2}{3}\)
\(x+\frac{2}{3}=3\frac{1}{3}\)
\(x+\frac{2}{3}=\frac{10}{3}\)
\(x=\frac{10}{3}-\frac{2}{3}\)
\(x=\frac{7}{3}\)
\(x+3\frac{1}{2}=\frac{1}{2}\)
\(x=\frac{1}{2}-3\frac{1}{2}\)
\(x=-3\)
x+3/1/2 =1/2
x=1/2 −3/1/2
x=−3