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\(P\left(x\right)=5^6-6.5^5+6.5^4-6.5^3+6.5^2-6.5+1=5^6-6\left(5^5-5^4-5^3-5^2-5\right)+1=1556\)
a: \(A=-5x^3+9x^3-2x^2-2x^2+x-x+1\)
\(=4x^3-4x^2+1\)
\(B=-4x^3+2x^3-2x^2+2x^2+6x-9x-2\)
\(=-2x^3-3x-2\)
\(C=x^3-6x^2+2x-4\)
b: \(A\left(x\right)+B\left(x\right)-C\left(x\right)\)
\(=4x^3-4x^2+1-2x^3-3x-2+x^3-6x^2+2x-4\)
\(=3x^3-10x^2-x-4\)
\(6x^2-2x\left(3x+\dfrac{3}{2}\right)=9\)
\(\Rightarrow6x^2-6x^2-3x=9\)
\(\Rightarrow-3x=9\)
\(\Rightarrow x=\dfrac{9}{-3}\)
\(\Rightarrow x=-3\)
\(6x^2-2x\left(3x+\dfrac{3}{2}\right)=9\\ \Leftrightarrow6x^2-6x^2-3x=9\\ \Leftrightarrow3x=9\\ \Leftrightarrow x=3\)
\(x^3-6x^2+5x=0\Leftrightarrow x\left(x^2-6x+5\right)=0\)
\(\Leftrightarrow x\left(x^2-x-5x+5\right)=0\)
\(\Leftrightarrow x\left[x\left(x-1\right)-5\left(x-1\right)\right]=0\Leftrightarrow x\left(x-1\right)\left(x-5\right)=0\Leftrightarrow x=0;x=1;x=5\)
\(x^3-6x^2+5x=0\)
\(\Leftrightarrow x.\left(x^2-6x+5\right)=0\)
\(\Leftrightarrow x.\left(x^2-x-5x+5\right)=0\)
\(\Leftrightarrow x.\left[\left(x^2-x\right)-\left(5x-5\right)\right]=0\)
\(\Leftrightarrow x.\left[x\left(x-1\right)-5\left(x-1\right)\right]=0\)
\(\Leftrightarrow x\left(x-1\right)\left(x-5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-1=0\\x-5=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\\x=5\end{matrix}\right.\)
Vậy \(x\in\left\{0;1;5\right\}\)
Ta có
1/2x+1/3x+1/6x+1=0
=>(1/2+1/3+1/6)x+1=0
=>1x+1=0
=>x=-1
Vậy x= -1
Ta có : x3 + 6x2 + 6x + 1 = 0
=> x3 + 6x2.1 + 6x.12 + 13 = 0
=> (x + 1)3 = 0
=> x + 1 = 0
=> x = -1
X^3+6x^2+6x+1=0
=>x^3+6x^2x1+6xx1^2+1^3=0
=>(x+1)^3=0
=> x+1=0
=>-1