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`x xx95+x+x:0,25=102,34`
`x xx95+x+x xx4=102,34`
`x xx(95+1+4)=102,34`
`x xx100=102,34`
`x=102,34:100=1,0234`
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x+x:0,5+x:0,25+x:0,125=2022\)
\(x\text{×}1+x\text{×}2+x\text{×}4+x\text{×8}=2022\)
\(x\text{×}\left(1+2+4+8\right)=2022\)
\(x\text{×}15=2022\)
\(x=2022:15\)
\(x=134,8\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`a)x xx96+x xx0,25=22,23`
`x xx96+x xx4=22,23`
`x xx(96+4)=22,23`
`x xx10=22,23`
`x=22,23:10=2,223`
`b)x:0,25+x xx95+x=10,23`
`x xx4+x xx95+x=10,23`
`x xx(4+95+1)=10,23`
`x xx10=10,23`
`x=10,23:10=1,023`
a: =>96x+4x=22,23
=>100x=22,23
hay x=0,2223
b: =>4x+95x+x=10,23
=>100x=10,23
hay x=0,1023
Tìm x,biết:
a)x*96+x:0,25=48,32
b)x:0,25+x+x*95=73,74
c)x:0,5+x:0,25+x+x*93=35,36
d)x:0,125+x+x*91=78,56
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>100x=48,32
hay x=0,4832
b: =>4x+x+95x=73,74
=>100x=73,74
hay x=0,7374
c: =>2x+4x+x+93x=35,36
=>100x=35,36
hay x=0,3536
a)Xx96+x:0,25=48,32
Xx96+Xx4 =48,32
X x(96+4) =48,32
Xx 100 =48,32
X =48,32:100
X = 0,4832
b)x:0,25+x+Xx95 =73,74
Xx4 +Xx1+Xx95= 73,74
X x(4+1+95) =73,74
X x 100 =73,74
X =73,74:100
X = 0,7374
c)x:0,5+x:0,25+x+Xx93=35,36
Xx2 + Xx4+Xx1+Xx93=35,36
Xx(2+4+1+93) = 35,36
Xx 100 = 35,36
X =35,36:100
X =0,3536
d)X:0,125+X+Xx91=78,56
Xx 8+Xx1+Xx91=78,56
Xx(8+1+91) =78,56
Xx 100 =78,56
X =78,56:100
X =0,7856
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có : 7962-136-x=1428
=>7800- x = 1428
=> x = 7800-1428
x = 6372
Vậy x = 6372
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x\left(45+1+54\right)=9872\)
\(x\times100=9872\)
\(x=9872:100\)
\(x=98.72\)
X x45 + X +X x 54 =9872
X x45 + Xx1 +Xx54=9872
X x ( 45 + 1 + 54) = 9872
X x 100 = 9872
X = 9872 : 100
X = 98,72
![](https://rs.olm.vn/images/avt/0.png?1311)
`x xx 95 + x + x : 0,25 = 7963`
`x xx (95 + 1 + 4) = 7963`
`x xx 100 = 7963`
`=> x = 79,63`.
\(x\times\left(95+1+4\right)=7963\)
\(100\times x=7963\)
\(x=79,63\)