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a) \(x+\frac{1}{2}=\frac{3}{4}\Rightarrow x=\frac{3}{4}-\frac{1}{2}\)\(\Rightarrow x=\frac{1}{4}\)
b)\(\frac{4}{5}\cdot x=\frac{4}{7}\Rightarrow x=\frac{4}{7}:\frac{4}{5}\)\(\Rightarrow x=\frac{5}{7}\)
c) \(8x=7,8x+25\Rightarrow8x-7,8x=25\)\(\Rightarrow0,2x=25\Rightarrow x=\frac{25}{0,2}\Rightarrow x=125\)
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x+1/2=3/4
x=3/4-1/2
x=6/8--4/8
x=2/8=1/4
4/5.x=4/7
x=4/7:4/5
x=4/7.5/4
x=5/7
![](https://rs.olm.vn/images/avt/0.png?1311)
` 8/23 . 46/24 =1/3 .x`
`=>8/23 . 23/12 =1/3 . x`
`=> 1/3 . x=2/3`
`=>x=2/3 : 1/3`
`=>x=2/3 . 3`
`=> x= 6/3`
`=>x=2`
`----`
`1/5 : x= 1/5-1/7`
`=>1/5 : x= 7/35 - 5/35`
`=> 1/5 :x= 2/35`
`=>x= 1/5 : 2/35`
`=>x=1/5 . 35/2`
`=>x=7/2`
`----`
`4/9 - (x-1/2)^2 =1/3`
`=> (x-1/2)^2 =4/9-1/3`
`=> (x-1/2)^2 =4/9- 3/9`
`=> (x-1/2)^2 =1/9`
`=> (x-1/2)^2 = (+- 1/3)^2`
`@ TH1`
`x-1/2=1/3`
`=>x=1/3+1/2`
`=>x= 2/6 + 3/6`
``=>x= 5/6`
`@ TH2`
`x-1/2=-1/3`
`=>x=-1/3 +1/2`
`=>x= -2/6 + 3/6`
`=>x=1/6`
`----`
`3,2 . x-(4/5+2/3) : 3 2/3 = 7/10`
`=> 3,2 . x-22/15 : 11/3 = 7/10`
`=> 3,2 . x-22/15 = 7/10 . 11/3`
`=> 3,2 . x-22/15 =77/30`
`=> 3,2 .x= 77/30 + 22/15`
`=> 3,2 .x=121/30`
`=>x= 121/30. 5/16`
`=>x= 121/96`
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`a)5/8x+2/5=1/5`
`=>5/8x=1/5-2/5`
`=>5/8x=-1/5`
`=>x=-1/5:5/8=-8/25`
`b)5/7:x+11/7=18/7`
`=>5/7:x=18/7-11/7`
`=>5/7:x=1`
`=>x=5/7`
`c)(-1,2).(-3/24)+(0,4-1 4/15):1 2/3`
`=(-6/5).(-1/8)+(2/5-19/15):5/3`
`=3/20+(-13/15)*3/5`
`=3/20-13/25=-37/100`
a)5/8.x+2/5=1/5
5/8.x=1/5 - 2/5
5/8.x=-1/5
x=(-1/5):5/8
x=(-1/5).8/5
x=-8/25. Vậy x=-8/25
b)5/7:x +11/7=18/7
5/7:x=1
x=5/7:1
x=5/7. Vậy x=5/7
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a, \(\left(\dfrac{1}{2}+\dfrac{4}{7}\right):x=\dfrac{-3}{4}\)
\(\dfrac{15}{14}:x=\dfrac{-3}{4}\)
=> x= \(\dfrac{-7}{10}\)
b, 0,5:x-\(1\dfrac{3}{4}\)= 25%
0,5:x-\(\dfrac{7}{4}=\dfrac{1}{4}\)
0,5:x = 2
=> x = \(\dfrac{1}{4}\)
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1/2 - (2/3x - 1/3) = 2/3
=> 1/2 - 2/3x + 1/3 = 2/3
=> 5/6 - 2/3x = 2/3
=> 2/3x = 5/6 - 2/3
=> 2/3x = 1/6
=> x = 1/6 : 2/3
=> x = 1/4
8x = 7,8x + 25
=> 8x - 7,8x = 25
=> 0,2x = 25
=> x = 25 : 0,2
=> x = 125
\(\frac{1}{2}-\left(\frac{2}{3}x-\frac{1}{3}\right)=\frac{2}{3}\)
\(\frac{1}{2}-\frac{2}{3}x+\frac{1}{3}=\frac{2}{3}\)
\(-\frac{2}{3}x=-\frac{1}{6}\)
\(x=\frac{1}{4}\)
\(8x=7,8x+25\)
\(02,x=25\)
\(x=125\)
=.= hk tốt!!
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a: \(16^x< 32^4\)
=>\(2^{4x}< 2^{20}\)
=>4x<20
=>\(x< 5\)
=>0<=x<5
=>\(x\in\left\{0;1;2;3;4\right\}\)
b: \(9< 3^x< 81\)
=>\(3^2< 3^x< 3^4\)
=>2<x<4
=>x=3
c: \(25< 5^x< 125\)
=>\(5^2< 5^x< 5^3\)
=>2<x<3
mà x là số tự nhiên
nên \(x\in\varnothing\)
a. x+1/2=3/4
x =3/4 - 1/2
x = 1/4
b. 4/5.x=4/7
x =4/7 : 4/5
x = 4/7 . 5/4
x = 5/7
c. 8x=7,8+25
8x=32,8
x= 32,8 : 8
x= 4,1
a) x=\(\frac{3}{4}-\frac{1}{2}\)
=\(\frac{1}{4}\)
b)x\(=\frac{4}{7}:\frac{4}{5}\)
x\(=\frac{4}{7}.\frac{5}{4}\)
x\(=\frac{5}{7}\)
c)8x= 32,8
x=4,1