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\(\dfrac{3}{5}+\left(x+2\right)=\dfrac{1}{5}\)
\(\Rightarrow x+2=\dfrac{1}{5}-\dfrac{3}{5}\)
\(\Rightarrow x+2=-\dfrac{2}{5}\)
\(\Rightarrow x=-\dfrac{2}{5}-2\)
\(\Rightarrow x=-\dfrac{12}{5}\)
\(x-5,14=15,7\)
\(\Rightarrow x=15,7+5,14\)
\(\Rightarrow x=20,84\)
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a) 4(x+41)=7
x+41=7/4
x=7/4-41
x=157/4
b) có gì đó sai sai-.-
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b) Ta có: \(x-43=\left(57-x\right)-50\)
\(\Leftrightarrow x-43=57-x-50\)
\(\Leftrightarrow x+x=7+43\)
\(\Leftrightarrow2x=50\)
hay x=25
Vậy: x=25
c) Ta có: (x-2)(8-x)=0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\8-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=8\end{matrix}\right.\)
Vậy: \(x\in\left\{2;8\right\}\)
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Bài 2:
a: Ta có: \(2x+79=x+45\)
nên 2x-x=45-79
hay x=-24
b: Ta có: \(15-\left(x+7\right)=\left(x-8\right)+22\)
\(\Leftrightarrow8-x-x-14=0\)
\(\Leftrightarrow2x=22\)
hay x=11
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a. 4.(x+41) = 7
x + 41 = 7 : 4 = 1,75
x = 1,75 - 41 = -39,25
b. 4.(x-3) = 72 - 110 = 49 - 1 = 48
x - 3 = 48 : 4 = 12
x = 12 + 3 = 15
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(4\left(x+41\right)=400\)
\(\Rightarrow x+41=400:4\)
\(\Rightarrow x+41=100\)
\(\Rightarrow x=100-41\)
\(\Rightarrow x=59\)
a) X + 3,12 = 6.1
X = 6.1 - 3.12
X= 2,98
b) X - 5,14 = 36
X = 36 + 5.14
X = 41.14
a) x+3,12=14,6-8,5
x+3,12=6,1
x = 6,1-3,12
x = 2,98
b) x-5,14=(15,7+2,3).2
x-5,14=36
x = 36+5,14
x = 41,14